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adoni [48]
3 years ago
8

Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).

Mathematics
1 answer:
Sveta_85 [38]3 years ago
8 0

Answer:

y = 4(x + 2)^2 - 20.

or in standard form it is

y = 4x^2+ 16x - 4.

Step-by-step explanation:

The equation in vertex form will be:

y = a(x + 2)^2 - 20   where a is some constant.

The y-intercept is (0, -12) so:

-12 = a(0 + 2) - 20

2a = -12 + 20 = 8

a = 4.

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Im pretty sure it’s right , just need someone to confirm it is
djyliett [7]
It’s correct. i like your handwriting btw, it’s really pretty
4 0
3 years ago
A rectangle measures 15 1/4 feet by 8 11/15 feet. If the length and width are extended by 1 2/3 Feet each find the area of the n
zubka84 [21]

Answer:

New area is 175 42/45 feet ²

Step-by-step explanation:

Given data

Length l= 15 1/4

To proper fraction = 61/4 feet

Width w= 8 11/15

To proper fraction = 131/15 feet

Extention = 1 2/3

To proper fraction = 5/3

Dimensions of new rectangle

Length =61/4+5/3 = 183+20/12

LCM = 12 = 203/12

Width = 131/15+5/3= 131+25/15

LCM = 15 = 156/15

Area = 203/12*156/15= =31668/180

=31668/180

= 7917/45

= 175 42/45 feet ²

6 0
3 years ago
If a point is translated down 6 Units what are the new coordinates expressed as an algebraic representation
Colt1911 [192]

Answer:

(x, y - 6)

Step-by-step explanation:

3 0
3 years ago
Determine which absolute value function represents this graph.
Valentin [98]

Answer: A

Step-by-step explanation:

4 0
3 years ago
NEED THIS DONE ASAP!! Thank you!!​
g100num [7]

Answer:

\overset{\frown}{WX}= 66^{\circ}

Step-by-step explanation:

<u>Inscribed Angle Theorem</u>

The measure of an <u>inscribed angle</u> is half the measure of the <u>intercepted arc</u>.

First, use the Inscribed Angle Theorem to calculate the measure of arc WY.

  \displaystyle \angle WXY=\dfrac{1}{2} \overset{\frown}{WY}

\implies 57^{\circ}=\dfrac{1}{2} \overset{\frown}{WY}

\implies \overset{\frown}{WY}= 2 \cdot 57^{\circ}

\implies \overset{\frown}{WY}= 114^{\circ}

Assuming XY is the diameter of the circle:

\implies \overset{\frown}{WY}+ \overset{\frown}{WX}= 180^{\circ}

\implies 114^{\circ} + \overset{\frown}{WX}= 180^{\circ}

\implies \overset{\frown}{WX}= 180^{\circ} - 114^{\circ}

\implies \overset{\frown}{WX}= 66^{\circ}

7 0
2 years ago
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