Find the x-intercepts of the parabola with vertex (-3,-18) and y-intercept at (0,0)
1 answer:
Y + 18 = a(x + 3)^2 <span>0 + 18 = a(0 + 3)^2 </span> <span>18 = 9a </span> <span>2 = a </span> <span>y = 2(x + 3)^2 - 18 </span> <span>0 = 2(x + 3)^2 - 18 </span> <span>18 = 2(x + 3)^2 </span> <span>9 = (x + 3)^2 </span> <span>± 3 = x + 3 </span> <span>-3 ± 3 = x </span> <span>x = 0 or -6 </span> <span>(0, 0) and (-6, 0)</span>
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