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3 years ago

What is/are the principal product(s) formed when excess methylmagnesium iodide reacts with p-hydroxyacetophenone?

Chemistry

1 answer:

Montano1993 [528]3 years ago

5 0

The end product will depend upon

a) the amount of the reagent taken

b) the final treatment of the reaction

If we have just taken methylmagnesium iodide and p-hydroxyacetophenone, then we will get methane and hydroxyl group substituted with MgI in place of hydrogen

Figure 1

However if we have taken excess of methylmagnesium iodide which is Grignard's reagent followed by hydrolysis we will get different product

Figure 2

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2 years ago

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Answer:

For a: The isotopic representation of iodine is $_{53}^{131}\textrm{I}$

For b: The isotopic representation of cesium is $_{55}^{137}\textrm{Cs}$

For c: The isotopic representation of strontium is $_{38}^{52}\textrm{Sr}$

Explanation:

The isotopic representation of an atom is: $_Z^A\textrm{X}$

where,

Z = Atomic number of the atom

A = Mass number of the atom

X = Symbol of the atom

For a:

We are given:

Number of neutrons = 78

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Mass number = 53 + 78 = 131

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For b:

We are given:

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Mass number = 55 + 82 = 137

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Number of neutrons = 52

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