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4 years ago

What is/are the principal product(s) formed when excess methylmagnesium iodide reacts with p-hydroxyacetophenone?

Chemistry

1 answer:

Montano1993 [528]4 years ago

5 0

The end product will depend upon

a) the amount of the reagent taken

b) the final treatment of the reaction

If we have just taken methylmagnesium iodide and p-hydroxyacetophenone, then we will get methane and hydroxyl group substituted with MgI in place of hydrogen

Figure 1

However if we have taken excess of methylmagnesium iodide which is Grignard's reagent followed by hydrolysis we will get different product

Figure 2

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solution was prepared by dissolving 43.0 g of KCl in 225 g of water. Part A Calculate the mole fraction of the ionic species KCl

notka56 [123]

Answer: The mole fraction of KCl in the solution is 0.044

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

For KCl:

Given mass of KCl = 43.0 g

Molar mass of KCl = 74.5 g/mol

Putting values in equation 1, we get:

$\text{Moles of KCl}=\frac{43g}{74.5g/mol}=0.58mol$

For water:

Given mass of water = 225 g

Molar mass of water = 18 g/mol

Putting values in equation 1, we get:

$\text{Moles of water}=\frac{225g}{18g/mol}=12.5mol$

To calculate the mole fraction of a substance, we use the equation:

$\chi_A=\frac{n_A}{n_A+n_B}$

Moles of KCl = 0.58 moles

Moles of water = 12.5 moles

Putting values in above equation:

$\chi_{KCl}=\frac{n_{KCl}}{n_{KCl}+n_{\text{water}}}$

$\chi_{KCl}=\frac{0.58}{0.58+12.5}\\\\\chi_{KCl}=0.044$

Hence, the mole fraction of KCl in the solution is 0.044

6 0

4 years ago

Which statements describe lattice energy? it is the energy the ions absorb when they form a crystalline compound. it increases a

musickatia [10]

The answers are:

It increases as the size of the ions decreases.

It increases as the charge on the ions increases.

It is a measure of the strength of the bonds between ions in a compound.

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4 years ago

Read 2 more answers

Rahul and Manav each were given a mixture of iron filings and sulphur powder. Rahul heated the mixture strongly and a new substa

AlexFokin [52]

Answer:

sure

Explanation:

The substance formed after heating the mixture of that of Rahul is caleed a compound. Whereas, Manav's mixture still remains in its current stae that is a heterogeneous mixture.

The compound formed is in black in color whereas the mixture is a mix of brownish-red and yellow.

The compound is a homogeneous mixture whereas the mixture is a heterogenous mixture because of its uneven distribution.

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3 years ago

¿cuáles son las ventajas de un experimento científico?

Ierofanga [76]

Answer:

Explanation:

Hacer proyectos de ciencia ayuda a desarrollar el ingenio de un niño

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3 years ago

Substances that dissolve in water nd give up OH-ions are considered what

just olya [345]

Your answer would be an Arrhenius base

Hope this helps

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2 years ago