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kolbaska11 [484]
3 years ago
13

What is/are the principal product(s) formed when excess methylmagnesium iodide reacts with p-hydroxyacetophenone?

Chemistry
1 answer:
Montano1993 [528]3 years ago
5 0

The end product will depend upon

a) the amount of the reagent taken

b) the final treatment of the reaction

If we have just taken methylmagnesium iodide and p-hydroxyacetophenone, then we will get methane and hydroxyl group substituted with MgI in place of hydrogen

Figure 1

However if we have taken excess of methylmagnesium iodide which is Grignard's reagent followed by hydrolysis we will get different product

Figure 2

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A chemist designs a galvanic cell that uses these two half-reactions:
Virty [35]

Answer:

MnO4⁻ (aq) + 8H⁺ (aq) + 5Fe³⁺ (aq) →Mn(aq)²⁺ + 4H2O (l) + 5Fe²⁺(aq)

Explanation:

a)

MnO4⁻ (aq) + 8H⁺ (aq) + 5e⁻ → Mn(aq)²⁺ + 4H2O (l)

b)

5Fe³⁺ (aq) +5e⁻ → 5Fe²⁺(aq)

c)

MnO4⁻ (aq) + 8H⁺ (aq) + 5Fe³⁺ (aq) →Mn(aq)²⁺ + 4H2O (l) + 5Fe²⁺(aq)

8 0
3 years ago
When 3.00 g of sulfur are combined with 3.00 g of oxygen, 6.00 g of sulfur dioxide (SO2) are formed. What mass of oxygen would b
Drupady [299]
Actually, we can answer the problem even without the first statement. All we have to do is write the reaction for the production of sulfur trioxide.

2 S + 3 O₂ → 2 SO₃

The stoichiometric calculations is as follows:

7 g S * 1 mol/32.06 g S = 0.218 mol S
Moles O₂ needed = 0.218 mol S * 3 mol O₂/2 mol S = 0.3275 mol O₂
Since the molar mas of O₂ is 32 g/mol,
Mass of O₂ needed = 0.3275 mol O₂ * 32 g/mol = 10.48 g O₂
3 0
3 years ago
What happens when a current is applied to two electrodes immersed in pure water?
frosja888 [35]
Nothing at all happens because pure water cannot conduct electricity
7 0
3 years ago
What is the daughter nuclide when 0-15 experiences positron emission?
Helen [10]

The daughter isotope (a decay product)of O-15 = N-15(Nitrogen 15)

<h3>Further explanation </h3>

Radioactivity is the process of unstable isotopes to stable isotopes by decay, by emitting certain particles,  

  • alpha α particles ₂He⁴
  • beta β ₋₁e⁰ particles
  • gamma particles γ
  • positron particles ₁e⁰

O-15 emits positron particles ₁e⁰, so the atomic number decreases by 1, the mass number is the same

Reaction

 \tt _8^{15}O\Rightarrow _7^{15}N+_1^0e

The mass number of the daughter isotope = 15, atomic number = 7

If we look at the periodic system, the element with atomic number 7 is Nitrogen (N)

5 0
3 years ago
What is the mass of an element with 15 protons, 13 electrons, and 11 neutrons? *
RSB [31]

Answer:

The mass of the element is 26.20 amu

Explanation:

In this question, we are asked to calculate the mass of an element with 15 protons, 13 electrons and 11 neutrons

To calculate the atomic mass of the element, we take into consideration the masses of the individual sub atomic particles

Electrons have 0 atomic mass unit(their masses are negligible) we have no business here, Protons have a mass of

1.00727647 amu, while the mass of neutron is 1.0086654 amu

The mass of 15 protons is thus 15 * 1.00727647 = 15.10914705 amu

The mass of 11 neutrons is 11 * 1.0086654 =

11.0953194 amu

Adding this together, we have ; 11.0953194 + 15.10914705 = approximately 26.20 amu

6 0
3 years ago
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