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Svetllana [295]
3 years ago
15

What is Centripetal force?

Chemistry
1 answer:
makvit [3.9K]3 years ago
6 0

A. A force that acts on a body moving in a circular path

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Which is a unit of density?<br><br> A) cm3/g <br> B) g/cm <br> C) g/cm3 <br> D) ml/g
tigry1 [53]
B}g/cm is a unit of density
4 0
3 years ago
Why does the dilution equation, M 1 V 1 = M 2 V 2, work?
valentina_108 [34]

Answer:

d) The dilution equation works because the number of moles remains the same.

Explanation:

Let’s say that you have 1 mol of a solute in I L of solution. The concentration is 1 mol·L⁻¹. and <em>M</em>₁<em>V</em>₁ = 1 mol.

Now, you dilute the solution to a volume of 2 L. You still have 1 mol of solute, but in 2 L of solution. The new concentration is 0.5 mol·L⁻¹.

The volume has doubled, but the volume has halved, and <em>M</em>₂<em>V</em>₂ = 1 mol.

b) <em>Wrong</em>. The molar concentration changes on dilution.

c) <em>Wrong</em>. The volume changes on dilution.

a) <em>Wrong</em>, although technically correct, because if the moles don’t change, the mass doesn’t change either. However, the formula <em>M</em>₁<em>V</em>₁ has units mol·L⁻¹ × L = mol. Thus, in the formula, it is moles that are constant.

6 0
4 years ago
Read 2 more answers
Please answer these for me
Dennis_Churaev [7]

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8 0
4 years ago
Describe what it would be like to be an atom
Bond [772]

Explanation:

An atom consists of two regions. The first is the tiny atomic nucleus, which is in the center of the atom and contains positively charged particles called protons and neutral, uncharged, particles called neutrons. ... Most atoms contain all three of these types of subatomic particles—protons, electrons, and neutrons.

3 0
3 years ago
1. How many moles are in 3.01 x 10^23 molecules of Boron trichloride
marishachu [46]

Answer: There are 0.499 moles present in 3.01 \times 10^{23} molecules of Boron trichloride.

Explanation:

According to mole concept, there are 6.022 \times 10^{23} molecules present in 1 mole of a substance.

Hence, number of moles present in 3.01 \times 10^{23} molecules are as follows.

Moles = \frac{3.01 \times 10^{23}}{6.022 \times 10^{23}}\\= 0.499 mol

Thus, we can conclude that there are 0.499 moles present in 3.01 \times 10^{23} molecules of Boron trichloride.

6 0
3 years ago
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