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earnstyle [38]
3 years ago
5

An average human being has about 5.0 L of blood in his or her body. If an average person were to eat 37.7 g of sugar (sucrose, ,

342.30 g/mol), and all that sugar were dissolved into the bloodstream, how would the molarity of the blood sugar change
Chemistry
1 answer:
Viktor [21]3 years ago
6 0

Answer: 0.0220275 M

Explanation:

So, we are given the following data or parameters which are going to help in solving this particular Question/problem.

=> Averagely, we have the volume = 5.0 L of blood in human body .

=> Mass of sugar eaten = 37.7 g of sugar (sucrose, 342.30 g/mol).

Therefore, the molarity of the blood sugar change can be calculated as below:

The molarity of the blood sugar change = (1/ volume) × mass/molar mass.

Thus, the molarity of the blood sugar change = (1/5) × 37.7/342.30 = 0.0220275 M.

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BALANCE the equation
Anna11 [10]

Answer:

1. 4FeCl3 + 3O2 → 2Fe2O3 + 6Cl2

2. 6 moles of Cl2

Explanation:

1. The balanced equation for the reaction. This is illustrated below:

4FeCl3 + 3O2 → 2Fe2O3 + 6Cl2

2. Determination of the number of mole of Cl2 produce when 4 moles of FeCl3 react with 4 moles. To obtain the number of mole of Cl2 produced, we must determine which reactant is the limiting reactant.

This is illustrated below:

From the balanced equation above,

4 moles of FeCl3 reacted with 3 moles of O2.

Since lesser amount of O2 (i.e 3 moles) than what was given (i.e 4 moles) is needed to react completely with 4 moles of FeCl3, therefore FeCl3 is the limiting reactant and O2 is the excess reactant.

Finally, we can obtain the number of mole Cl2 produced from the reaction as follow:

Note: the limiting reactant is used as it will produce the maximum yield of the reaction since all of it is used up in the reaction.

From the balanced equation above,

4 moles of FeCl3 will react to produced 6 moles of Cl2.

8 0
3 years ago
An ideal gas in a cylindrical container of radius r and height h is kept at constant pressure p. The bottom of the container is
Juli2301 [7.4K]

Answer:

m =\frac{p*(pi)*r^{2}*h*mw}{R*\frac{T_{1} + T_{O}}{2}}  

Explanation:

The gas ideal law is  

PV= nRT (equation 1)

Where:

P = pressure  

R = gas constant  

T = temperature  

n= moles of substance  

V = volume  

Working with equation 1 we can get  

n =\frac{PV}{RT}

The number of moles is mass (m) / molecular weight (mw). Replacing this value in the equation we get.

\frac{m}{mw} =\frac{PV}{RT}  or  

m =\frac{P*V*mw}{R*T}   (equation 2)

The cylindrical container has a constant pressure p  

The volume is the volume of a cylinder this is

V =(pi)*r^{2}*h

Where:

r = radius  

h = height  

(pi) = number pi (3.1415)

This cylinder has a radius, r and height, h so the volume is  V =(pi)*r^{2}*h

Since the temperatures has linear distribution, we can say that the temperature in the cylinder is the average between the temperature in the top and in the bottom of the cylinder. This is:  

T =\frac{T_{1} + T_{O}}{2}  

Replacing these values in the equation 2 we get:

m =\frac{P*V*mw}{R*T}   (equation 2)

m =\frac{p*(pi)*r^{2}*h*mw}{R*\frac{T_{1} + T_{O}}{2}}    

8 0
3 years ago
What is the mass of air in room
tigry1 [53]

Answer:

the mass of the air in the room is 4.96512 kg ( in 0°C)

3 0
3 years ago
Jenny measures the temperature inside a cave to be 10°C. The temperature outside the cave is about 30°C warmer. How does the kin
ExtremeBDS [4]
<h2>Answer:</h2>

<em><u>The kinetic energy of the air molecules in the cave is less than the kinetic energy of molecules outside the cave.</u></em>

<h3>Explanation:</h3>

The kinetic energy of any molecule is directly proportional to the temperature of the gas.

Temperature of a gas is the heat energy provided to the molecules. As the temperature energy increase the molecules of the gas will move fastly and collide with each other.

So we can know the kinetic energy of molecules in the gas by measuring its temperature.

Hence the temperature of the cave is less than outside, so the kinetic energy will also be low.

8 0
3 years ago
Read 2 more answers
What are three ways to measure the amount of something chemistry?
AleksandrR [38]
There are three ways to measure the amount of something in chemistry.

1. There is a simple count which is tabulating the amount of something present. 

2. You can measure the mass which is the amount of matter in something. 

3. You can measure the volume which is the amount of three dimensional space occupied by a closed surface.
8 0
3 years ago
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