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neonofarm [45]
4 years ago
6

Buffy is rolling along in her 10.4 kg wagon at 3.4 m/s (in the positive direction) when she jumps off the back. She continues to

move forward at 1.7 m/s relative to the ground. This causes her wagon to go speeding forward at 8.04 m/s relative to the ground. How much does Buffy weigh
Physics
1 answer:
lubasha [3.4K]4 years ago
4 0

Answer:

Buffy weigh's 28.39 kg

Explanation:

Given;

mass of Buffy and wagon, M = 10.4 kg

final velocity of Buffy - wagon system, v = 3.4 m/s

Buffy's velocity relative to the ground, u₁ = 1.7 m/s

Wagon's velocity relative to the ground, u₂ = 8.04 m/s

Buffy's velocity = 1.7 - 3.4 = - 1.7 m/s

Wagon's velocity = 8.04 - 3.4 = 4.64 m/s

Apply the principle of conservation of linear momentum;

1.7 x m = 4.64 x 10.4

where;

m is mass of wagon

1.7 m = 48.256

m = 48.256 / 1.7

m = 28.39 kg

Therefore, Buffy weigh's 28.39 kg

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Norma-Jean [14]

Answer:

q = 2,95 10-6 C

Explanation:

The magnetic force on a particle is described by the equation

      F = q v x B

Where bold indicate vectors

Let's make the vector product

      vxB =\left[\begin{array}{ccc}i&j&k\\-3&4&12\\0&0&-0.13\end{array}\right]

                     

      v x B = 1.20 106 [i ^ (4 0.130) - j ^ (3 0.130)]

      vx B = 1.20 106 [0.52 i ^ - 0.39j ^]

As they give us the force module, let's use Pythagoras' theorem,

     |v xB | =1.20 10⁶ √( 0.52² + 0.39²)

    |v x B| = 1.20 10⁶ 0.65

     v xB = 0.78 10⁶

Let's replace and calculate

    2.30 = q 0.78 10⁶

    q = 2.3 / 0.78 106

    q = 2,95 10-6 C

4 0
3 years ago
Arunning back practices for his upcoming football game by running drills. He runs forward 62.4 yards, and runs backward for
Mama L [17]

Answer: He has only move 0.2 yards

Explanation: When you subtract 18.3 from 18.5 you get 0.2 and that is how much he's moved

4 0
3 years ago
Football player 1 has a mass of 80 kg and a velocity of 2 m/s east while player 2 has a mass of 70 kg and a velocity of 3 m/s we
sukhopar [10]

The total momentum of the system is equal to 50 Kgm/s.

<u>Given the following data:</u>

  • Mass 1 = 80 kg
  • Velocity 1 = 2 m/s east.
  • Mass 2 = 70 kg
  • Velocity 2 = 3 m/s west.

To determine the total momentum of the system:

Mathematically, momentum is given by the formula;

Momentum = mass \times velocity

<u>For Football player 1:</u>

Momentum = 80 \times 2

Momentum 1 = 160 Kgm/s.

<u>For Football player 2:</u>

Momentum = 70 \times 3

Momentum 1 = 210 Kgm/s.

Now, we can calculate the total momentum of the system:

Total\;momentum = momentum \;2 - momentum \;1\\\\Total\;momentum = 210-160

Total momentum = 50 Kgm/s.

<u>Note:</u> We subtracted because the football players were moving in opposite directions.

Read more: brainly.com/question/15517471

6 0
3 years ago
If Earth's mass was cut in half, what would happen to your mass? Group of answer choices
Alex777 [14]

Answer:

nothing, mass is not affected by gravitational force

Explanation:

Weight is the gravitational force a planet exerts on a mass on the surface.

It is the product of the mass of an object with the gravitational acceleration that the planet produces.

The weight is the gravitational force

W=mg

where,

m = Mass of the object

g = Acceleration due to gravity = 9.81 m/s²

Mass is the property that matter has which opposes the force being applied to it. It is intrinsic to the object itself and does not change according to the gravitational force. But, the weight changes.

5 0
4 years ago
Work of 2 joules is done in stretching a spring from its natural length to 11 cm beyond its natural length. what is the force (i
Sidana [21]
The law applied here is Hooke's Law which describes the force exerted by the spring with a given distance. The equation for this is F = kΔx, where F is the force in Newtons, k is the spring constant in N/m while Δx is the displacement in meters.

If you want to find work done by a spring, this can be solved by using differential equations. However, derived equations are already ready for use. The equation is

W = k[{x₂-x₁)² - (x₁-xn)²],

where 
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x₁ is the stretched length 
x₂ is also the stretched length when stretched even further than x₁

In this case xn =x₁. So, that means that (x₁-xn) = 0 and (x₂-x₁) = 11 cm or 0.11 m.

Then, substituting the values,

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Finally, we use the value of k to the Hooke's Law to determine the Force.

F = kΔx = (165.29 N/m)(0.11 m)
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