Answer:
v =3.41 m/s
Explanation:
given,
mass of block 1 = 6 Kg
mass of another block 2 = 4 Kg
coefficient of friction = 0.3
Assuming 6 Kg block is attached to the spring of spring constant 350 N/m
and distance between the two block is equal to 0.5 m
using formula
U = 43.75 J
using conservation of energy
KE = U - f.d
where f is the frictional force acting
v =3.41 m/s
Answer: 
Explanation:
Given
Cross-sectional area 
Dielectric constant 
Dielectric strength 
Distance between capacitors 
Maximum charge that can be stored before dielectric breakdown is given by
![\Rightarrow Q=CV\\\\\Rightarrow Q=\dfrac{k\epsilon_oA}{d}\cdot (Ed)\quad\quad [V=E\cdot d]\\\\\Rightarrow Q=k\epsilon_oAE\\\\\Rightarrow Q=4\times 8.85\times 10^{-12}\times 0.4\times 10^{-4}\times 2\times 10^8\\\\\Rightarrow Q=28.32\times 10^{-8}\\\\\Rightarrow Q=283.2\times 10^{-9}\ nC](https://tex.z-dn.net/?f=%5CRightarrow%20Q%3DCV%5C%5C%5C%5C%5CRightarrow%20Q%3D%5Cdfrac%7Bk%5Cepsilon_oA%7D%7Bd%7D%5Ccdot%20%28Ed%29%5Cquad%5Cquad%20%5BV%3DE%5Ccdot%20d%5D%5C%5C%5C%5C%5CRightarrow%20Q%3Dk%5Cepsilon_oAE%5C%5C%5C%5C%5CRightarrow%20Q%3D4%5Ctimes%208.85%5Ctimes%2010%5E%7B-12%7D%5Ctimes%200.4%5Ctimes%2010%5E%7B-4%7D%5Ctimes%202%5Ctimes%2010%5E8%5C%5C%5C%5C%5CRightarrow%20Q%3D28.32%5Ctimes%2010%5E%7B-8%7D%5C%5C%5C%5C%5CRightarrow%20Q%3D283.2%5Ctimes%2010%5E%7B-9%7D%5C%20nC)
Answer:
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B. Inelastic collision.
In elastic collision , both momentum and kinetic energy are conserved while in inelastic collision only momentum is conserved. there is some loss of energy in inelastic collision during collision.
During the collision of bat with baseball, some energy gets lost to heat and sound. hence the kinetic energy is not conserved although the momentum is conserved.
