All categories

3 years ago

Encuentre la presion en la otra seccion estrecha si las velocidades en las secciones son de 0.50m\sy 2m\s

Physics

1 answer:

Igoryamba3 years ago

4 0

Answer:

ΔP = 1875 Pa, P₂ = P₁ - 1875

Explanation:

Let's use Bernoulli's equation, with the subscript 1 for the widest Mars and the subscript 2 for the narrowest part, suppose that the pipe is horizontal

P₁ + ½ ρ v₁² + ρ g y₁ = P₂ + ½ ρ v₂² + ρ g y₂

P₁ -P₂ = ½ ρ (v₂² - v₁²)

suppose the fluid is water

P₁ - P₂ = ½ 1000 (2² - 0.5²)

ΔP = 1875 Pa

this is the pressure difference between the two sections

the pressure in the narrowest section is

P₂ = P₁ - 1875

You might be interested in

An electron is a negatively charged particle that has a charge of magnitude, e - 1.60 x 10-19 C. Which one of the following stat

Ivahew [28]

Answer:

The electric field is directed toward the electron and has a magnitude of $E=\frac{ke}{r^{2} }$ .

Explanation:

An electric field is define as the surrounding of charges which exert a force on each other and this force can be attractive or repulsive depends on the charge.

In the given case electron is given and the magnitude of charge on electron is $e=1.6\times 10^{-19}C$

Electric field can be represented as,

$E=\frac{kQ}{r^{2} }$

Here, r is the distance between the point ande charge, k is the electric field constant and Q is the charge.

In the given question an electron is given so electric field will be,

$E=\frac{ke}{r^{2} }$

As we know that electric field start from the positive charge and vanish in the negative charge.

So, here the electric field will be $E=\frac{ke}{r^{2} }$ and it is directed toward the electron because of negative charge on the electron.

6 0

3 years ago

A satellite at a particular point along an elliptical orbit has a gravitational potential energy of 4700 MJ with respect to Eart

erastovalidia [21]

during satellite motion we know that total energy is always conserved

so here we will have

$KE_i + PE_i = KE_f + PE_f$

here we know that

$KE_i = 4800 MJ$

$PE_i = 4700 MJ$

now at other position

$PE_f = 6000 MJ$

now from above equation we have

$4800 +4700 = 6000 + KE$

now we have

$9500 = 6000 + KE$

$KE = 9500 - 6000 = 3500 MJ$

so its kinetic energy will be 3500 MJ

6 0

3 years ago

) Water flows through a horizontal coil heated from the outside by high-temperature flue gases. As it passes through the coil th

Mademuasel [1]

Explanation:

Formula for steady flow energy equation for the flow of fluid is as follows.

$m[h_{1} + \frac{V^{2}_{1}}{2}] + z_{1}g] + q = m[h_{1} + \frac{V^{2}_{1}}{2} + z_{1}g] + w$

Now, we will substitute 0 for both $z_{1}$ and $z_{2}$ , 0 for w, 334.9 kJ/kg for $h_{1}$ , 2726.5 kJ/kg for $h_{2}$ , 5 m/s for $V_{1}$ and 220 m/s for $V_{2}$ .

Putting the given values into the above formula as follows.

$m[h_{1} + \frac{V^{2}_{1}}{2}] + z_{1}g] + q = m[h_{1} + \frac{V^{2}_{1}}{2} + z_{1}g] + w$

$1 \times [334.9 \times 10^{3} J/kg + \frac{(5 m/s)^{2}}{2} + 0] + q = 1 \times [2726.5 \times 10^{3} + \frac{(220 m/s)^{2}}{2} + 0] + 0$

q = 6597.711 kJ

Thus, we can conclude that heat transferred through the coil per unit mass of water is 6597.711 kJ.

6 0

3 years ago

Question: A 0.50 m wave has a frequency of 686 Hz. What is the speed of the wave?

Dafna1 [17]

C. 340
Frequency is the number of wavelengths per second and since the length is 0.5 you multiply 0.5*686 and get 343.
the question not allowing for one position thus the answer is c

7 0

3 years ago

1.05 MEASURING PHYSICAL PROPERTIES LAB REPORT

Nana76 [90]

Answer:

Objective(s): In your own words, what was the purpose of this lab?

The purpose of this lab is to get us familiar with the physical properties of different types of materials that are used for building.

Hypothesis: In this section, include the if/then statements you developed during your lab activity. These statements reflect your predicted outcomes for the experiment.

If we use clay brick to build the roof of the house, then the temperature inside the house will remain cooler.

If we use wood to build the walls and floors of the house, then the temperature inside the house will remain cooler.

If we use nickel to bring electricity into the home, then it will allow electricity to flow into the home at a faster rate.

If we use iron to construct the latches on the windows and doors, then the magnetism will keep the latches secure.

Procedure: The materials and procedures are listed in your virtual lab. You do not need to repeat them here. However, you should note if you experienced any errors or other factors that might affect your outcome.

Using the summary questions, clearly define the dependent and independent variables of the experiment.

Data: Record the results of each of your physical property tests in the table below.

Wood _ 3/10 _0 _0.12 W/(m·K) _0 S/m _ 4 g/cm3

Clay Brick _ 2/10 _1 _0.6 W/(m·K) _ 0 S/m _ 5.88235 g/cm3

Iron _ 4/10 _10 _80 W/(m·K) _1x107 S/m _9.09091 g/cm3

Aluminum_ 7/10 _ 0 _235 W/(m·K) _ 3.8x107 S/m _ 6.66667 g/cm3

Copper _ 6/10 _0 _400 W/(m·K) _3.8x107 S/m _9.52381 g/cm3

Nickel _ 5/10 _7 _ 91 W/(m·K) _1.4x107 S/m _9.43396 g/cm3

Conclusion: Your conclusion will include a summary of the lab results and an interpretation of the results. Please answer all questions in complete sentences using your own words.

Using two to three sentences, summarize what you investigated and observed in this lab.

In this, I investigated the effect that different types of physical properties had on six different materials. I also investigated which materials would be the best to build a house.

2. What building material did you use to build your house? Did your results support or fail to support your hypotheses?

For the roof of my house, I used clay bricks. For the walls and floors of the house, I used wood. To bring electricity into the home I used nickel. To construct the latches on the windows and doors, I used iron. My results supported my hypotheses because clay bricks and wood had the lowest thermal conductivity rates, nickel had the second highest electricity conductivity rate, and iron had the highest magnetism rate.

3. What were the densities of the materials you chose for the walls and floor for the home in Tiny World? Why do you think a building material's density is important when building homes or architectural structures?

The density of the material I chose for the walls and floors for the home in Tiny World was 4 g/cm3 (Wood). I think a buildings material density is important when building homes or architectural structures because in order for that structure to stay stable the materials that are used must be dense. If the materials are not dense, the structure would most likely collapse if it is placed under too much pressure.

4. Why wouldn’t you choose wood or aluminum for the latches on your house?

I wouldn’t choose wood or aluminum for the latches on my house because neither of those two materials are magnetic.

5. Which material has the highest thermal conductivity? Which material has the highest electrical conductivity? Explain why thermal and electrical conductivity is so high with this material.

Copper has the highest thermal conductivity. Aluminum and copper have the highest electrical conductivity. Thermal conductivity is high in copper because copper is a very thin type of material, and this allows heat to pass through it easily. Electric Conductivity is high in both aluminum and copper because they are both a very thin type of metal and because they are both so thin, electricity will pass through them quickly.

I'm sorry if any of the answers are wrong, this was just assigned to me and my teacher hasn't graded it yet.

4 0

3 years ago