Is there a multiple choice?
That's going to depend on the initial velocity, and how it changes
or doesn't change during the 2.6 seconds. I've read the question,
and Im pretty sure you didn't tell us any of that.
Answer:
p = 22.5 cm
Explanation:
For this exercise we must use the equation of the constructor
where f is the focal length, p and q are the distance to the object and the image respectively.
Let's start with the far point, the object is very far away (p = ∞) and the image must be formed at the far point of view of the person q = 45.0 cm
since the image is on the same side as the object according to the sign convention the distance is negative
f = -45.0 cm
now let's use the near point (q = 15.0 cm) at what distance the object should be
1 / p = 1 / -45 - 1 / -15
1 / p = -1/45 + 1/15
= 0.0444
p = 22.5 cm
this is the closest distance you can see an object clearly
<span>High photon energy, high frequency, sub-optical wavelength</span>