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3 years ago

Which is the MOST accurate statement about the heating curve and energy?

Physics

2 answers:

statuscvo [17]3 years ago

6 0

Answer: A) Moving from A to C the temperature and the kinetic energy increases.

Explanation: Moving from A to C the temperature and the kinetic energy increases. As the temperature of a substance increases, the movement or kinetic energy also increases.

V125BC [204]3 years ago

3 0

The answer is A). Moving from A to C the temperature and the kinetic energy increases.

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The pressure exerted by a gas is 2.0 atm while it has a volume of 350 mL. What would be the volume of this sample of gas at stan

34kurt

Answer:

700 mL or 0.0007 m³

Explanation:

P₁ = Initial pressure = 2 atm

V₁ = Initial volume = 350 mL

P₂ = Final pressure = 1 atm

V₂ = Final volume

Here the temperature remains constant. So, Boyle's law can be applied here.

P₁V₁ = P₂V₂

$\frac{P_1V_1}{P_2}=V_2\\\Rightarrow V_2=\frac{2\times 350}{1}\\\Rightarrow V_2=700\ mL$

So, volume of this sample of gas at standard atmospheric pressure would be 700 mL or 0.0007 m³

7 0

3 years ago

Determine the kinetic energy of 1000-kg roller coaster car that is moving with speed of 20.0m/s

nevsk [136]

B, i got the same question

7 0

3 years ago

What is the acceleration of a car going 50 mph that slows down to rest over 10 seconds?

VladimirAG [237]

Answer:

If the velocity is constant, then there is no acceleration. That is, the value of the acceleration is 0.

Explanation:

6 0

3 years ago

Perpendicular slope to 3x-y=4

Mashcka [7]

Perpendicular slope would be 1/3. so the equation will be Y=1/3x -4

4 0

3 years ago

Projectile Motion—A tennis ball is thrown out a window 28 m above the ground at an initial velocity of 15.0 m/s and 20.0° below

NNADVOKAT [17]

Answer:

The distance will be x = 41.7 [m]

Explanation:

We must first find the components in the x & y axes of the initial velocity.

$(v_{o})_{x} = 15*cos(20)= 14.09[m/s]\\(v_{o})_{y} = 15*sin(20)= 5.13[m/s]$

The acceleration is the gravity acceleration therefore.

g = 9.81 [m/s^2]

Now we can calculate how long it takes to fall.

$y=(v_{o})_{y}*t-0.5*g*t^2\\-28 = 5.13*t-0.5*9.81*t^2\\-28=-4.905*t^2+5.13*t\\4.905*t^2-5.13*t=28\\t = 2.96[s]$

With this time we can find the horizontal distance that runs the projectile.

$x=(v_{o})_{x}*t\\x=14.09*2.96\\x=41.7[m]$

5 0

2 years ago