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jekas [21]
3 years ago
13

Will mark brainliest!! Answer fast and correct.

Physics
1 answer:
geniusboy [140]3 years ago
6 0

Answer:

The. Layers. Of. Earth. Has. Different temperatures so. They. Will. Have. Different. Particles

Explanation:

Mantle outerlayer. Etc. Different (can. I. Have. Brainliest. Please

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The doctor writes a prescription for na heparin 20,000 units in 500 ml n.s. infuse over 8 hours. what is the flow rate in ml/hr?
Ne4ueva [31]
I think this type of equation could be conducted in simple division equation since it does not involve drop rate.

we know that there is 500 ml of substance and should be infused within 8 hours period.

So the flow rate in ml/hr would be: 

500/8 = 62.5 ml/hr                                                                                    
8 0
3 years ago
Identify the normal force on the shopping cart after 75 newtons of groceries are added to the cart
Anna71 [15]
If the shopping cart is parallel to the ground, the weight is acting vertically downward, then force is equal to weight. The normal force will be acting perpendicular to the ground,and acting upward opposite of the weight.
3 0
3 years ago
Read 2 more answers
Cierto volumen de gas se encuentra a 60°c de temperatura y 5atm de presión, es calentado hasta 140°c, estado en el cual ocupa un
earnstyle [38]

Answer:

V1 = 2221.33 L

Explanation:

The system is about a ideal gas. Then you can use the equation for ideal gases for a volume V1, temperature T1 and pressure P1:

P_1V_1=nRT_1   (1)

And also for the situation in which the variables T, V and P has changed:

P_2V_2=nRT_2   (1)

R: constant of ideal gases = 0.082 L.atm/mol.K

For both cases (1) and (2) the number of moles are the same. Next, you solve for n in (1) and (2):

n=\frac{P_1V_1}{RT_1}\\\\n=\frac{P_2V_2}{RT_2}

Next, you equal these equations an solve for T2:

\frac{P_1V_1}{RT_1}=\frac{P_2V_2}{RT_2}\\\\V_1=\frac{P_2V_2T_1}{P_1T_2}

Finally you replace the values of P2, V2, T1 and T2:

V_1=\frac{(7atm)(680L)(140\°C)}{(60\°C)(5atm)}=2221.33\ L

Hence, the initial volume of the gas is 2221.33 L

5 0
4 years ago
When the arrow is released, how does the the force on the arrow (by the bow) compare to the force on the archer (by the bow)?
Jet001 [13]

Answer:

hello some parts of your question is missing below is the complete question

A 60.0 kg archer standing on a friction-less ice shoots a 100g arrow at a speed of 80.0 m/s to the right .When the arrow is released, how does the the force on the arrow (by the bow) compare to the force on the archer (by the bow)?

Answer : The force on the arrow is larger than the force on the archer because the arrow has a higher final velocity

Explanation:

we can compare The force on the arrow  to the force on the archer by using the final velocities of the archer and the arrow ,hence The force on the arrow is larger than the force on the archer because the arrow has a higher final velocity and this is according to Newton's law which states for a every action there is an equal reaction i.e the force applied on the arrow will be the opposite of the force on the archer

5 0
3 years ago
Which statement descThe image shows the right-hand rule being used for a current-carrying wire.
Makovka662 [10]
Answer:

The second option.
When the current flows up the wire, the magnetic field flows out on the left side of the wire and in on the right side of the wire.

Explanation:

The first figure that I copy here with is the figure corresponding to this question.

The thumb is pointing upward.

The rule is that the thumb aims to the direction of the flow of current and the other fingers give the field lines.

The second figure that I attach is a free image from internet and it shows the direction of both the current and the fiedl lines.

So, the conclusion is that the current goes upward the wire and the field lines go out of the paper (screen) for the points to the left of the wire and in on the right side of the wire.

4 0
3 years ago
Read 2 more answers
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