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torisob [31]
3 years ago
15

You riding in a car traveling at a speed of 73 mi/hr in a. 60 mi/hr zone, when suddenly you spot a police car parked 20 ft ahead

of you. Do you hit the brakes and slow down with an acceleration of -2 ft/sec,for a total time of 3 seconds. Do you get a ticket?
Physics
2 answers:
fenix001 [56]3 years ago
5 0
I think yes i do.. cuz using yr information i get the distance i travelled before stopping become 49.62144 m, using the formula distance travelled/time taken= (final velocity+initial velocity)/2.
I am not sure tht its the right answer but using my calculation I got this so hope there! :)
Nataliya [291]3 years ago
4 0

Answer:

You get a ticket you speed is around 68 mi/hr

Explanation:

V_{f} =V_{i} + a*t

V_{i} = 73 \frac{mi}{hr} *\frac{1 hr}{3600 s} * \frac{1609,34m}{1 mi} = 32.6339 \frac{m}{s}, a=-2 \frac{ft}{s^{2} } * \frac{0.3048m}{1 ft} =-0.6096 \frac{m}{s^{2} }

V_{f} =32.6339\frac{m}{s}  -0.6096 \frac{m}{s^{2} } *3 s

V_{f} = 30.8051\frac{m}{s} *\frac{3600 s}{hr} * \frac{1 mi}{1609.34m} = 68.909 \frac{mi}{hr}

You still in trouble because  the speed is still above the allowed

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<em> The space in seconds that will be kept = 2.27 seconds</em>

Explanation:

S = d/t..................... Equation 1

making t the subject of formula in the equation above,

t = d/S.................... Equation 2

Where S = speed, d = distance, t = time.

<em>Conversion: (i)if 1 mph = 0.44704 m/s,</em>

<em>                 then, 30 mph = 30×0.44704    </em>

<em>                = 13.41 m/s</em>

<em>               (ii) If 1 foot = 0.3048 m</em>

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<em>Given: S = 30 mph = 13.41 m/s, d = 100 foot = 30.48 m</em>

<em>Substituting these values into equation 2</em>

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