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torisob [31]
3 years ago
15

You riding in a car traveling at a speed of 73 mi/hr in a. 60 mi/hr zone, when suddenly you spot a police car parked 20 ft ahead

of you. Do you hit the brakes and slow down with an acceleration of -2 ft/sec,for a total time of 3 seconds. Do you get a ticket?
Physics
2 answers:
fenix001 [56]3 years ago
5 0
I think yes i do.. cuz using yr information i get the distance i travelled before stopping become 49.62144 m, using the formula distance travelled/time taken= (final velocity+initial velocity)/2.
I am not sure tht its the right answer but using my calculation I got this so hope there! :)
Nataliya [291]3 years ago
4 0

Answer:

You get a ticket you speed is around 68 mi/hr

Explanation:

V_{f} =V_{i} + a*t

V_{i} = 73 \frac{mi}{hr} *\frac{1 hr}{3600 s} * \frac{1609,34m}{1 mi} = 32.6339 \frac{m}{s}, a=-2 \frac{ft}{s^{2} } * \frac{0.3048m}{1 ft} =-0.6096 \frac{m}{s^{2} }

V_{f} =32.6339\frac{m}{s}  -0.6096 \frac{m}{s^{2} } *3 s

V_{f} = 30.8051\frac{m}{s} *\frac{3600 s}{hr} * \frac{1 mi}{1609.34m} = 68.909 \frac{mi}{hr}

You still in trouble because  the speed is still above the allowed

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For a caffeinated drink with a caffeine mass percent of 0.65% and a density of 1.00 g/mL, how many mL of the drink would be requ
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Explanation:

First we will convert the given mass from lb to kg as follows.

        157 lb = 157 lb \times \frac{1 kg}{2.2046 lb}

                   = 71.215 kg

Now, mass of caffeine required for a person of that mass at the LD50 is as follows.

         180 \frac{mg}{kg} \times 71.215 kg

         = 12818.7 mg

Convert the % of (w/w) into % (w/v) as follows.

      0.65% (w/w) = \frac{0.65 g}{100 g}

                           = \frac{0.65 g}{(\frac{100 g}{1.0 g/ml})}

                           = \frac{0.65 g}{100 ml}

Therefore, calculate the volume which contains the amount of caffeine as follows.

   12818.7 mg = 12.8187 g = \frac{12.8187 g}{\frac{0.65 g}{100 ml}}

                       = 1972 ml

Thus, we can conclude that 1972 ml of the drink would be required to reach an LD50 of 180 mg/kg body mass if the person weighed 157 lb.

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