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KiRa [710]
3 years ago
9

A wave oscillates 5.0 times a second and has a speed of 8.0 m/s .What is the frequency of this wave?

Physics
1 answer:
lianna [129]3 years ago
8 0

Answer:

f = 5.0 times a second or 5.0 Hz

Explanation:

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A charge of 4.5 × 10-5 C is placed in an electric field with a strength of 2.0 × 104 . If the charge is 0.030 m from the source
ololo11 [35]

Answer:

0.027 J

Explanation:

The formula of the potential energy in electrostatic (U) is

U = q \times E \times d

The values given in the question are

Charge : q = 4.5 \times 10^{-5} C

Electric Field strength : E = 2.0 \times 10^{4} N/C

Distance : d  is 0.030 m

Insert in the formula , will give us

U = 4.5 \times 10^{-5} C \times 2.0 \times 10^{4} N/C \times 0.030 m

Further solving it

U = 0.027 J

Which is the required answer.

Thanks

5 0
3 years ago
The radius of a sphere is increasing at a rate of 4 mm/s. how fast is the volume increasing when the diameter is 40 mm?
marin [14]

Using <span>r </span> to represent the radius and <span>t </span> for time, you can write the first rate as:

<span><span><span><span>dr</span><span>dt</span></span>=4<span>mms</span></span> </span>

or

<span><span>r=r<span>(t)</span>=4t</span> </span>

The formula for a solid sphere's volume is:

<span><span>V=V<span>(r)</span>=<span>43</span>π<span>r3</span></span> </span>

When you take the derivative of both sides with respect to time...

<span><span><span><span>dV</span><span>dt</span></span>=<span>43</span>π<span>(3<span>r2</span>)</span><span>(<span><span>dr</span><span>dt</span></span>)</span></span> </span>

...remember the Chain Rule for implicit differentiation. The general format for this is:

<span><span><span><span><span>dV<span>(r)</span></span><span>dt</span></span>=<span><span>dV<span>(r)</span></span><span>dr<span>(t)</span></span></span>⋅<span><span>dr<span>(t)</span></span><span>dt</span></span></span> </span>with <span><span>V=V<span>(r)</span></span> </span> and <span><span>r=r<span>(t)</span></span> </span>.</span>

So, when you take the derivative of the volume, it is with respect to its variable <span>r </span> <span><span>(<span><span>dV<span>(r)</span></span><span>dr<span>(t)</span></span></span>)</span> </span>, but we want to do it with respect to <span>t </span> <span><span>(<span><span>dV<span>(r)</span></span><span>dt</span></span>)</span> </span>. Since <span><span>r=r<span>(t)</span></span> </span> and <span><span>r<span>(t)</span></span> </span> is implicitly a function of <span>t </span>, to make the equality work, you have to multiply by the derivative of the function <span><span>r<span>(t)</span></span> </span> with respect to <span>t </span> <span><span>(<span><span>dr<span>(t)</span></span><span>dt</span></span>)</span> </span>as well. That way, you're taking a derivative along a chain of functions, so to speak (<span><span>V→r→t</span> </span>).

Now what you can do is simply plug in what <span>r </span> is (note you were given diameter) and what <span><span><span>dr</span><span>dt</span></span> </span> is, because <span><span><span>dV</span><span>dt</span></span> </span> describes the rate of change of the volume over time, of a sphere.

<span><span><span><span><span>dV</span><span>dt</span></span>=<span>43</span>π<span>(3<span><span>(20mm)</span>2</span>)</span><span>(4<span>mms</span>)</span></span> </span><span><span>=6400π<span><span>mm3</span>s</span></span> </span></span>

Since time just increases, and the radius increases as a function of time, and the volume increases as a function of a constant times the radius cubed, the volume increases faster than the radius increases, so we can't just say the two rates are the same.

7 0
3 years ago
Will give 30 points!!!
AysviL [449]
The answer is C I believe
8 0
3 years ago
Read 2 more answers
How are motors and generators different?
saw5 [17]
A generator converts mechanical energy into electrical energy, while a motor does the opposite - it converts electrical energy into mechanical energy
4 0
3 years ago
An aquifer pump test was conducted in a confined aquifer where the initial piezometric surface was at elevation 12.45 m, and wel
murzikaleks [220]

Answer:

T = 0.0088 m²/s

Explanation:

given,

initial piezometric elevation = 12.5 m

thickness of aquifer = 14 m

discharge = 28.24 L/s = 0.02824 m³/s

we know                              

k = \dfrac{qln(\dfrac{R_2}{R_1})}{2\pi D(H_2-H_1)}

k = \dfrac{0.02824 \times ln(\dfrac{75}{25})}{2\pi \times 14 (11.45-10.89)}                                                                        

k = 0.629 mm/sec

Transmissibilty

T = k × H                          

T = 0.629 × 14 × 10⁻³

T = 0.0088 m²/s

4 0
3 years ago
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