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KiRa [710]
3 years ago
9

A wave oscillates 5.0 times a second and has a speed of 8.0 m/s .What is the frequency of this wave?

Physics
1 answer:
lianna [129]3 years ago
8 0

Answer:

f = 5.0 times a second or 5.0 Hz

Explanation:

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Explain whether there can be forces act-
Xelga [282]

Technically friction is acting on the car because it is still rubbing against the street and gravity is pulling the car down preventing it from floating??? lol

5 0
2 years ago
How do you calculate the net force when there are multiple forces in different directions?​
Artyom0805 [142]

To find F_{net} we need to use vector addition and use the x and y components. First we subtract vector 2 from vector 5 which results in a vector with a  length of 3 pointing directly east, then we use the distance formula to find the length of the net force F_{net} = \sqrt{(3)^2+(4)^2} \\  which gives F_{net} = 5. We now have a magnitude but we also need a direction, since vector 4 and vector 5 are perpendicular. Using \theta = \tan^{-1} (\frac{4}{3})   where tan^-1(y/x) we get an angle of 53 degrees. The resultant force vector is 5 distance with an angle of 53 degrees north east.

4 0
3 years ago
If the absolute pressure of a gas is 550.280 kPa, its gage pressure is A. 101.325 kPa. B. 651.605 kPa. C. 448.955 kPa. D. 277.28
guajiro [1.7K]

Answer:

Option C is the correct answer.

Explanation:

Absolute  pressure is sum of gauge pressure and atmospheric pressure.

That is

               P_{abs}=P_{gauge}+P_{atm}

We have

          P_{abs}=550.280 kPa\\\\P_{atm}=1atm=101325Pa=101.325kPa

Substituting

         P_{abs}=P_{gauge}+P_{atm}\\\\550.280=P_{gauge}+101.325\\\\P_{gauge}=448.955kPa

Option C is the correct answer.

7 0
3 years ago
Write a difference between force and work? ​
Nesterboy [21]

Answer:

force is a derived quantity

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2.Force is measured in Newton why work is measured in Newton per seconds (N/s)

Explanation:

no

3 0
2 years ago
Read 2 more answers
A charged sphere with 1 × 10 8 units of negative charge is brought near a neutral metal rod. The half of the rod closer to the s
jeyben [28]

Answer:

-4*10⁴ units.

Explanation:

As the metal rod was initially neutral (which means that it has the same quantity of positive and negative charges), after being close to the charged sphere, as charge must be conserved, the total charge of the metal rod must  still remain to be zero.

So, if due to the influence of the negative charge in the sphere, the half of the road closer to the sphere has a surplus charge of +4*10⁴ units, the charge on the half of the rod farther from the sphere must be the same in magnitude but of the opposite sign, i.e., -4*10⁴ units.

5 0
2 years ago
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