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Vilka [71]
3 years ago
8

Light waves have some similarities with water and sound waves, but they are not exactly the same. Describe all the differences y

ou can think of between light waves, sound waves, or water waves.
I NEED AT LEAST 7 PLEASE OR THE ANSWER WILL BE CONSIDERED INCOMPLETE
Physics
1 answer:
makkiz [27]3 years ago
3 0

<u>Answer:</u>


<h2>All the waves are pertubations that propagate (transport) energy.</h2><h2></h2>

Nevertheless, they have some differences:


1. Light waves are<u> electromagnetic waves</u>, while sound and water waves are <u>mechanical waves</u>, this is the first and principal difference.  

2. Electromagnetic waves can<u> propagate in vacuum</u> (they do not need a medium or material), but mechanical waves obligatory need a material to propagate

3. Light waves are always <u>transversal waves</u>, this means <u>the oscillatory movement is in a direction that is perpendicular to the propagation</u>; but mechanical waves may be both: <u>longitudinal waves</u> (the oscillation occurs in the same direction as the propagation) or transversal waves.

4. Electromagnetic waves propagates at a <u>constant velocity</u> (Light velocity) while the velocity of mechanical waves will depend on the type of wave and the <u>density</u> of the medium or material.

5. <u>Mechanical waves</u> are characterized by the regular variation of a single magnitude, while <u>electromagnetic waves</u> are characterized by the variation of two magnitudes: the electric field and the magnetic field

6. <u>Water waves</u> are 2-dimensional waves, while the <u>light and the sound</u> are tridimensional spherical waves

7. Light waves <u>transports energy in the form of </u><u>radiation</u>, while mechanical waves t<u>ransport energy with </u><u>material</u>


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Now we know that velocity = distance/ time

And acceleration = velocity/time.


From the graph we see that at the time interval 2 secs,the distance travelled is 10 m. Hence the velocity(v1) =10/2 = 5m/s.

From the graph we see that at the time interval 5 secs,the distance travelled is 25 m. Hence the velocity (v2) =25/5 = 5m/s.

Now acceleceration between the time interval of 2 ad 5 secs is calculated as

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Find the magnitude of the side and the angle. Please help!
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Answer:

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<em>Assuming the triangle is a right triangle,</em>

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It is given that,

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So, \dfrac{W_A}{W_N}=\dfrac{mg-\dfrac{mv^2}{r}}{mg}

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or

\dfrac{W_A}{W_N}=71.9\%

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