The first-serve percentage of a
tennis player in a match is normally distributed with a standard deviation of
4.3%. If a sample of 15 random matches of
the player is taken, the mean
first-serve percentage is found to be 26.4%. The margin of error of the sample
mean is 83.71%.
Answer:
1. 500
2. 126
3. 615
Step-by-step explanation:
Area of a parallelogram formula: A = bh
20 x 25 = 500
7 x 18 = 126
20.5 x 30 = 615
To get the answer we can use proportion
220 ----------------95.3%
x -------------------100%
Crossmultiply now
220*100%=95.3%*x
22000=95.3x /:95.3
22000:95.3=x
231=x - its the answer
Answer:
0
Step-by-step explanation:
They all seem to be plotted correctly in accordance with the graph
Answer:
Be an GH
Step-by-step explanation:
