Which statements about density curves are true? Check all that apply.
1 answer:
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Answer:
There is no minimum cost for the fencing that can satisfy these conditions.
as the equation obtained for this problem is y = .
Step-by-step explanation:
let length of the rectangular rose garden be x
and breath of the rectangular rose garden be y
then the area of the garden = xy
cost of fencing a foot for the 3 non road sides = $6
and cost of fencing a foot for a road side = $8
total cost of fencing = 6x + 8x + 6y + 6y
so, total cost = 14x + 12y
cost of fencing for every square foot of the area =$2
So, 2xy = 14x + 12y
=> 2xy = 14x + 12y
Also, x and y has to satisfy x>0 and y>0
You can solve for y (or x if you prefer)
2xy-12y=14x
xy - 6y = 7x
y(x-6)=7x
y =
we can check that this function has no minimum value.
as we increase x (starting any x > 6 to make y positive) to make y minimal, y will decrease but the product xy will increase.
So, there is not a minimum cost for fencing that can satisfy these conditions.
Answer:
Step-by-step explanation:
Hello!
There are some values missing, so I'll find the probability distribution using others as example. Afterwards you can calculate the ones corresponding to this exercise following the same steps.
Considering there are 5000 undergraduates registered in the college.
465 are taking one course
658 are taking two courses
566 are taking three courses
1877 are taking four courses
1344 are taking five courses
90 are taking six courses
First you have to define the variable of interest. To identify it you have to ask yourself the following question: what is the characteristic of this population that is being measured?
The answer is "the number of courses an undergraduate is taking" and this will be the study variable X
X can take values from 1 to 6 courses.
To calculate the probability of each value of X, you have to divide the "number of students taking Xi courses" by "total number of students registered in the college"
For
X=1
P(1)= 465/5000= 0.093
X=2
P(2)= 658/5000= 0.1316
X=3
P(3)= 566/5000= 0.1132
X=4
P(4)= 1877/5000= 0.3754
X=5
P(5)= 1344/5000= 0.2688
X=6
P(6)= 90/5000= 0.018
For this to be a probability distribution the following condition should be met:
F(X)= ∑P(X) = 1
In this example: 0.093 + 0.1316 + 0.1132 + 0.3754 + 0.2688 + 0.018 = 1
I hope this helps!
