Question

Factor the perfect square trinomial on the left side of the equation

Answer 1

Answer:

$(x+\frac{1}{4})^2=\frac{4}{9}$

Step-by-step explanation:

Given the the equation

$x^2+\frac{1}{2}x+\frac{1}{16}=\frac{4}{9}$

We have to factor the perfect square trinomial on the left side of the equation

$x^2+2\times x\times \frac{1}{4}+(\frac{1}{4})^2=\frac{4}{9}$

As, $(a+b)^2=a^2+2ab+b^2$

Here LHS makes the perfect square

$(x+\frac{1}{4})^2=\frac{4}{9}$

Answer 2

Answer:

1/4

Step-by-step explanation:

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