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tankabanditka [31]
3 years ago
10

Please answer this and thank you If DF=78, DE=5x-9, and EF=2x+10, find EF.

Mathematics
2 answers:
gregori [183]3 years ago
6 0
DE + EF = DF
5x - 9 + 2x + 10 = 78
7x+ 1 = 78
7x = 77
x = 77/7 = 11

EF = 2x + 10
EF = 2*11 + 10
EF = 22 + 10
EF = 32
AleksAgata [21]3 years ago
6 0

Question

If DF = 78, DE = 5x-9, and EF = 2x+10, find EF.

Answer

EF = 32

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Answer:

14

Step-by-step explanation

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Kyle needs to build a crate in the shape of a rectangular prism. The crate must have a volume of 160 cubic feet, and a height of
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<u>40 sq. ft.</u>

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2 years ago
4x - 2y = -14<br> 3х - у = -8
oksian1 [2.3K]

are you trying to add them all together if so here how that would work

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6 0
3 years ago
Factories A, B and C produce computers. Factory A produces 4 times as manycomputers as factory C, and factory B produces 7 times
Elina [12.6K]

Answer:

The  probability is   P(A') =  0.485

Step-by-step explanation:

Let assume that the number of computer produced by factory C is  k = 1  

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        The  probability of defective computers from A is  P(A) =  0.04

        The  probability of defective computers from B is  P(B)  =  0.02

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Now the probability of factory A producing a defective computer out of the 4 computers produced is  

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substituting values

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The probability of factory B producing a defective computer out of the 7 computers produced is  

       P(b) = 7  *  P(B)

substituting values

        P(b) =  7 * 0.02

        P(b) = 0.14

The probability of factory C producing a defective computer out of the 1 computer produced is  

       P(c) = 1  *  P(C)

substituting values

        P(c) =  1 * 0.03

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     P(t) =  P(a) +  P(b) +  P(c)

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     P(t) =   0.16  + 0.14 +  0.03

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Now the probability that the defective computer is produced from factory A is

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3 0
3 years ago
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