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Delicious77 [7]
3 years ago
7

Find the perimeter of the following polygon. Be sure to include the correct unit in your answer.

Mathematics
1 answer:
Natalija [7]3 years ago
3 0

Answer:

The answer is 48yd.

Step-by-step explanation:

All you have to do is add up the numbers.

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Brianna solved a two-step equation, but she made a mistake along the way.
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The appropriate choice is ...

... On Line 3, Brianna should have divided by 0.1 instead of subtracting 0.1.

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Had Brianna simplified her effort properly on line 4, she would have

... -0.1 +0.1x = -1.4

putting her essentially back where she started—with a 2-step equation.

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3 years ago
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Please help me please
irakobra [83]

Answer:

D

Step-by-step explanation:

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we choose a sample of size 100 from a population of monthly cable bills having standard deviation $20 If we assume the populatio
igor_vitrenko [27]

Answer:

0.0062

Step-by-step explanation:

Find the standard error.

σ = 20 / √100

σ = 2

Find the z-score.

z = (x − μ) / σ

z = (70 − 65) / 2

z = 2.5

Find the probability.

P(Z > 2.5) = 1 − 0.9938

P(Z > 2.5) = 0.0062

8 0
3 years ago
On an uphill hike, Ted climbs at a rate of 3 miles an hour. Going down, he runs at a rate of 5 miles an hour. If it takes him 40
andreyandreev [35.5K]
Let the total length of Ted's hike be L and the total time spent be T.

The time spent going down is t, and the time spent going up is t+40 (if t is measured in minutes) or t + 2 hr/3 (if t is measured in hours).  Note that t + t + 2/3 must equal T, the total hiking time, with all measurerments in hours.

Distance uphill:  L = (3 mph)(t+2/3) = Distance downhill:  (5 mph)(t)

We need only find t, the am't of time req'd for Ted to go up to down.

3t + 2 = 5t, or 2 = 2t, or t = 1 (hour)

It will take Ted 1 hour to descend the hill and 1 2/3 hour to ascend the hill.

The total length of Ted's hike was then 2 2/3 hours, or 2 hours 40 minutes.

By the way, the distance in each direction is (5 mph)(1 hr) = 5 miles.  
6 0
3 years ago
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A streetlight sits on top of a 20-foot pole. A six-foot tall man walks away from the pole at a rate of 5 ft/sec. At what rate is
guajiro [1.7K]

Answer:

\frac{25}{3}ft/s

Step-by-step explanation:

We are given that

Height of pole,h=20 foot

Height of man,h'=6 foot

\frac{dx}{dt}=5ft/s

We have to find the rate at which the man's shadow growing when the man is 10 feet from the pole.

Let x be the distance of man from the pole and  y be the distance of tip of man's shadow from the pole.

Distance between man and shadow's tip=y-x

When two triangle are similar then the ratio of their corresponding sides are equal.

\frac{6}{15}=\frac{y-x}{y}

6y=15y-15x

15x=15y-6y=9y

y=\frac{15}{9}x=\frac{5}{3}x

Differentiate w.r.t t

\frac{dy}{dt}=\frac{5}{3}\frac{dx}{dt}=\frac{5}{3}\times 5=\frac{25}{3}ft/s

Hence, the man's shadow growing at rate \frac{25}{3}ft/s when the man is 10 feet from the pole.

4 0
3 years ago
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