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3 years ago

PLEASE HELP!!!

Mathematics

2 answers:

GalinKa [24]3 years ago

7 0

Answer:

40 pounds of candy worth $1.25

30 pounds of candy worth $1.60

Step-by-step explanation:

1.25x + 112 -1.6x = 98

-0.35x = -14

0.35x = 14

x= 40 pounds

70 pounds in total - 40 pounds = 30

y = 30 pounds

attashe74 [19]3 years ago

6 0

He used 40 pounds of the candy worth $1.25 and 30 pounds of the candy worth $1.6.

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Read 2 more answers

The average maximum monthly temperature in Campinas, Brazil is 29.9 degrees Celsius. The standard deviation in maximum monthly t

kvv77 [185]

Answer:

$P(X>32)=P(\frac{X-\mu}{\sigma}>\frac{32-\mu}{\sigma})=P(Z>\frac{32-29.9}{2.31})=P(z>0.909)$

And we can find this probability with the complement rule and using the normal standard distributon table or excel we got:

$P(z>0.909)=1-P(z$

And if we convert this to a % we got 18.2 % of maximum temperatures higher or equal than 32 C

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the maximum monthly temperature of a population, and for this case we know the distribution for X is given by:

$X \sim N(29.9,2.31)$

Where $\mu=29.9$ and $\sigma=2.31$

We are interested on this probability

$P(X>32)$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(X>32)=P(\frac{X-\mu}{\sigma}>\frac{32-\mu}{\sigma})=P(Z>\frac{32-29.9}{2.31})=P(z>0.909)$

And we can find this probability with the complement rule and using the normal standard distributon table or excel we got:

$P(z>0.909)=1-P(z$

And if we convert this to a % we got 18.2 % of maximum temperatures higher or equal than 32 C

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3 years ago