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Vinvika [58]
3 years ago
13

Solve by substitution

Mathematics
2 answers:
Tomtit [17]3 years ago
8 0
X= -46 and y = -40 I worked it out I might be wrong
MArishka [77]3 years ago
5 0
Y= 6+X
3x-4(6+x) = -22
3x-4x = -22 + 24
-x= 2
X= -2

Sub back into first equation
Y= 6-2
Y= 4
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Please help me, What is 640.31 written in expanded form?
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Read 2 more answers
What is number 61 and a step by step explaination please?
astra-53 [7]

1/3 ln(<em>x</em>) + ln(2) - ln(3) = 3

Recall that m\log_b(n)=\log_b(n^m), so

ln(<em>x</em> ¹ʹ³) + ln(2) - ln(3) = 3

Condense the left side by using sum and difference properties of logarithms:

\log_b(m)+\log_b(n)=\log_b(mn)

\log_b(m)-\log_b(n)=\log_b\left(\dfrac mn\right)

Then

ln(2/3 <em>x</em> ¹ʹ³) = 3

Take the exponential of both sides; that is, write both sides as powers of the constant <em>e</em>. (I'm using exp(<em>x</em>) = <em>e</em> ˣ so I can write it all in one line.)

exp(ln(2/3 <em>x</em> ¹ʹ³)) = exp(3)

Now exp(ln(<em>x</em>)) = <em>x </em>for all <em>x</em>, so this simplifies to

2/3 <em>x</em> ¹ʹ³ = exp(3)

Now solve for <em>x</em>. Multiply both sides by 3/2 :

3/2 × 2/3 <em>x</em> ¹ʹ³ = 3/2 exp(3)

<em>x</em> ¹ʹ³ = 3/2 exp(3)

Raise both sides to the power of 3:

(<em>x</em> ¹ʹ³)³ = (3/2 exp(3))³

<em>x</em> = 3³/2³ exp(3×3)

<em>x</em> = 27/8 exp(9)

which is the same as

<em>x</em> = 27/8 <em>e</em> ⁹

3 0
3 years ago
The output with the y being -4
aivan3 [116]

For this case we have a function of the form y = f (x), where f (x) = - 4x. We must find the values of "and" according to the following function:y = -4x

So:

f (-6) = - 4 (-6) = 24\\f (-2) = - 4 (-2) = 8\\f (3) = - 4 (3) = - 12

Thus, the values are:

24,8, -12

Answer:

24,8, -12

3 0
3 years ago
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