If you're looking for the angle it is a 30, 60, 90, but if you're looking for the length of the hypotenuse it's 5
Answer:
A) 48 in : initial height of the water
B) 40.5 in : height of the water after 5 days
C) 32 days
D) Yes, should be restricted.
Domain: 0 ≤ d ≤ 32
Step-by-step explanation:
A)
48 in is the initial height of the water
B)
40.5 in is the height of the water after 5 days
C) when the pool is empty, h = 0.
So set the equation to zero and solve for d.
D) Yes, the domain should be restricted because when d > 32, h < 0 and the height of the water in the pool cannot be negative
Domain: 0 ≤ d ≤ 32
Answer:
Step-by-step explanation:
t1 = a1
t2 = a1 + d
t3 = a1 + 2d
The sum is t1 + t2 + t3 = a1 + a1 + d + a1 + 2d = 3a1 + 3d
Second question
t1 = a1
t2 = a1 + d
t3 = a1 + 2d
t4 = a1 + 3d
...
tn = a1 + (n - 1)*d
Sum = (a1 + a1 + (n- 1)*d) * n / 2
Sum = (2a1 + nd - d) * n / 2
Sum = (2a1*n + n^2*d - nd) / 2
Answer:
Should be, (-3,5) (if rise over run aka y,x)
Step-by-step explanation:
When attempting to find a slope like this, you need to locate pretty points. Pretty points are any time the line meets an exact corner on the box. If you look at -3,1, you can see the line makes a pretty point there. Then, try to find the next one, which is at 2,-3. Once you found these pretty points, try to connect them by drawing a line towards each other THAT IS STRAIGHT until those intersect. Where they intersect is where the slope of the line is. In this case, when I drew the line, they met at <em>down three</em>, <em>over (right) 5.</em>
