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Umnica [9.8K]
3 years ago
8

[ 6.5 ] In the space below, briefly explain why the average times for the two CO2 molecules you calculated should have been simi

lar (or at least not significantly different). If a CO2 molecule starts out surrounded by other CO2 molecules, does this influence how quickly it will reach the other side of the leaf? You might find it helpful to reset the simulation and to re-examine the initial configurations of molecules. Collisions influence how molecules move, but do molecules only collide with other molecules of the same substance?
Chemistry
1 answer:
julsineya [31]3 years ago
5 0

Answer:

This question is incomplete

Explanation:

This question is incomplete but there are two parts to this question that can generally be answered without the missing parts.

(1) If a CO₂ molecule starts out surrounded by other CO₂ molecules, does this influence how quickly it will reach the other side of the leaf?

What controls how quickly a CO₂ molecule/molecules enter into the leaf to the other parts of a leaf is the stomata on the leaf. Stomata are tiny openings on a plant leaf that allows for gaseous exchange (the release of oxygen and the absorption of CO₂) in the leaf.

(2)  Collisions influence how molecules move, but do molecules only collide with other molecules of the same substance? NO

One of the kinetic theory of gases states that gases collide with one another and against the walls of the container. <u>It should however be noted that, gas molecules of a particular substance can collide with gas molecules of other substances</u>, so far they are within the same container.

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Explain whether changing the ratio of baking soda and vinegar changes the amount of carbon dioxide produced. Include the evidenc
PilotLPTM [1.2K]

Answer:

Reducing the amount of vinegar will reduce the amount of carbon dioxide produced because there will be fewer molecules of acetic acid to react with the baking soda and produce the carbon dioxide.

To make more carbon dioxide, you could add either more acetic acid or more sodium bicarbonate or more of both.

Explanation:

Hope it helps! ^_^

5 0
3 years ago
Using the Assignment: Locating the Epicenter, What was the length of the radius of the circle of from the Buenos Aires station?
svetoff [14.1K]
It may be 4.8cm? Tell me if i’m wrong or right. I’m so sorry if it’s wrong.
6 0
3 years ago
The airbags that protect people in car crashes are inflated by the extremely rapid decomposition of sodium azide, which produces
Oxana [17]

Answer:

1. NaN₃(s) → Na(s) + 1.5 N₂(g)

2. 79.3g

Explanation:

<em>1. Write a balanced chemical equation, including physical state symbols, for the decomposition of solid sodium azide (NaN₃) into solid sodium and gaseous dinitrogen.</em>

NaN₃(s) → Na(s) + 1.5 N₂(g)

<em>2. Suppose 43.0L of dinitrogen gas are produced by this reaction, at a temperature of 13.0°C and pressure of exactly 1atm. Calculate the mass of sodium azide that must have reacted. Round your answer to 3 significant digits.</em>

First, we have to calculate the moles of N₂ from the ideal gas equation.

P.V=n.R.T\\n=\frac{P.V}{R.T} =\frac{1atm.(43.0L)}{(0.08206atm.L/mol.K).286.2K} =1.83mol

The moles of NaN₃ are:

1.83molN_{2}.\frac{1molNaN_{3}}{1.5molN_{2}} =1.22molNaN_{3}

The molar mass of NaN₃ is 65.01 g/mol. The mass of NaN₃ is:

1.22mol.\frac{65.01g}{mol} =79.3g

5 0
3 years ago
A 1.00 g sample of octane (C8H18) is burned in a bomb calorimeter with a heat capacity of 837J∘C that holds 1200. g of water at
lubasha [3.4K]

Answer:

The heat of combustion for 1.00 mol of octane is  -5485.7 kJ/mol

Explanation:

<u>Step 1:</u> Data given

Mass of octane = 1.00 grams

Heat capacity of calorimeter = 837 J/°C

Mass of water = 1200 grams

Temperature of water = 25.0°C

Final temperature : 33.2 °C

<u> Step 2:</u> Calculate heat absorbed by the calorimeter

q = c*ΔT

⇒ with c = the heat capacity of the calorimeter = 837 J/°C

⇒ with ΔT = The change of temperature = T2 - T1 = 33.2 - 25.0 : 8.2 °C

q = 837 * 8.2 = 6863.4 J

<u>Step 3:</u> Calculate heat absorbed by the water

q = m*c*ΔT

⇒ m = the mass of the water = 1200 grams

⇒ c = the specific heat of water = 4.184 J/g°C

⇒ ΔT = The change in temperature = T2 - T1 = 33.2 - 25  = 8.2 °C

q = 1200 * 4.184 * 8.2 =  41170.56 J

<u>Step 4</u>: Calculate the total heat

qcalorimeter + qwater = 6863.4 + 41170. 56 = 48033.96 J  = 48 kJ

Since this is an exothermic reaction, there is heat released. q is positive but ΔH is negative.

<u>Step 5</u>: Calculate moles of octane

Moles octane = 1.00 gram / 114.23 g/mol

Moles octane = 0.00875 moles

<u>Step 6:</u> Calculate heat combustion for 1.00 mol of octane

ΔH = -48 kJ / 0.00875 moles

ΔH = -5485.7 kJ/mol

The heat of combustion for 1.00 mol of octane is  -5485.7 kJ/mol

8 0
3 years ago
The bond between which two atoms is most polar
otez555 [7]

Answer:

bond

Explanation:

It is a polar bond because it is when two atoms bond

4 0
3 years ago
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