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3 years ago

Butane methane ethane propane

Chemistry

1 answer:

aleksklad [387]3 years ago

7 0

<h3>Further explanation</h3>

Given

the structure of the alkanes

Required

match the image to the name

Solution

Alkanes are saturated hydrocarbons with all of the carbon bonds being single bonds

General formula:

$\large {\boxed {\bold {C_nH_2n + 2}}}$

If we look at the picture, we define the black atom as Carbon and the branch is Hydrogen

To determine the name of the alkane, all we have to do is count the number of Carbon atoms

Butane : C₄H₁₀ : 4 C atoms

Methane : CH₄ : 1 C atom

Ethane : C₂H₆ : 2 C atoms

Propane : C₃H₈ : 3 C atoms

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Ethanol, C2H6O, is most often blended with gasoline - usually as a 10 percent mix - to create a fuel called gasohol. Ethanol is

ch4aika [34]

Answer:

4054 kcal of heat is released during complete combustion of 354 g of octane.

Explanation:

Heat of combustion of 1 mol of octane is $1.308\times 10^{3}$ kcal

Molar mass of octane = 114.23 g/mol

We know, no. of moles = (mass)/(molar mass)

So, $1.308\times 10^{3}$ kcal of heat is released during complete combustion of 114.23 g of octane.

So, amount of heat is released during complete combustion of 354 g of octane = $(\frac{1.308\times 10^{3}}{114.23})\times 354$ kcal = 4054 kcal

Hence 4054 kcal of heat is released during complete combustion of 354 g of octane.

5 0

3 years ago

Which complex ion can exhibit geometric isomerism? Assume that M is the metal ion, A and B are ligands, and the geometry is octa

Archy [21]

Answer:

[MA4B2]2+

Explanation:

Octahedral species are species that has a coordination number of of six. This means that six ligands are attached to the central metal atom/ion.

For any octahedral specie to exhibit geometrical or cis-trans isomerism, it must have the formula EX2Y4 as in [MA4B2]2+, hence the answer above.

7 0

4 years ago

Sand dunes protect beaches against erosion and flooding due to storms.

kogti [31]

Answer:

B. Building houses near the beach

Explanation:

it was right on edge

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4 years ago

Read 2 more answers

How many L of carbon dioxide at 1.00 atm and 298.15 K are released from a car's engine upon consumption of a 60.0 L LIQUID tank

torisob [31]

Answer:

79,000 liters

Explanation:

1. Number of moles of gasoline

a) Convert 60.0 liters to grams

density = 0.77kg/liter

density = mass / volume

mass = density × volume

mass = 0.77kg/liter × 60.0 liter = 46.2 kg

46.2kg × 1,000g/kg = 46,200g

b) Convert 46,200 grams to moles

molar mass of C₈H₁₈ = 114.2 g/mol

number of moles = mass in grams / molar mass

number of moles = 46,200g / (114.2 gmol) = 404.55 mol

2. Number of moles of carbon dioxide, CO₂ produced

a) Balanced chemical equation (given):

C₈H₁₈ (l) + ²⁵/₂ O₂ (g) → 8 CO₂ (g) + 9 H₂O (g)

b) mole ratio:

1 mol C₈H₁₈ / 8 mol CO₂ = 404.55 mol C₈H₁₈ / x

Solve for x:

x = 404.55mol C₈H₁₈ × 8 mol CO₂ / 1mol C₈H₁₈ = 3,236.4 mol CO₂

3. Convert the number of moles of carbon dioxide to volume

Use the ideal gas equation:

pV = nRT

V = nRT/p

p = 1 atm

T = 298.15K

n = 3,236.4 mol

R = 0.08206 (mol . liter)/ (K . mol)

Substitute and compute:

V =3,236.4 mol × 0.08206 (mol . liter) / (K . mol) 298.15K / 1 atm

V = 79,183 liter

Round to two significant figures (because the density has two significant figures): 79,000 liters ← answer

3 0

3 years ago

Will mark brainliest for correct answer!!! Need help ASAP :"))

Andrews [41]

Answer:

So the balanced chemical equation would look like this:

4NO + 6 $H_{2}$ O -> 4N $H_{3}$ + 5 $O_{2}$

sorry i dont k how to find the moles when im already given a value :(

Explanation:

3 0

3 years ago