N2 + 3H2 = 2NH3
in this question, we are dealing with only NH3 and H2 so we only focus on that
since the ratio of H2 to 2NH3 is 3:2, we say that
3 liters of H2 = 2 liters of 2NH3
3.6 litres of H2 = x liters of 2NH3
We cross multiple to give:
3 × x = 3.6 × 2
3x = 7.2
Divide both sides by 3
x = 7.2 ÷ 3
x = 2.4liters
Answer:
2.8
Explanation:
First, we will calculate the molarity of the acetylsalicylic acid solution.
M = mass of solute (g) / molar mass of solute × volume of solution (L)
M = 0.327 g / 180.158 g/mol × 0.237 L
M = 7.66 × 10⁻³ M
For a weak acid such as acetylsalicylic acid, we can find the concentration of H⁺ using the following expression.
[H⁺] = √(Ca × Ka)
where,
Ca: concentration of the acid
Ka: acid dissociation constant
[H⁺] = √(7.66 × 10⁻³ × 3.3 × 10⁻⁴)
[H⁺] = 1.6 × 10⁻³ M
The pH is:
pH = -log [H⁺]
pH = -log 1.6 × 10⁻³ = 2.8
Answer:
82500000000000000000000000
Explanation:
This is the only answer I can come up with.
