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Svet_ta [14]
3 years ago
5

Given side lengths of 40 cm, 70 cm, and 80 cm, how many triangles can be constructed?

Mathematics
2 answers:
Salsk061 [2.6K]3 years ago
7 0
One with 40cm being the side, 70 diagonal and 80 as the base so it is a right angle triangle
JulijaS [17]3 years ago
3 0

Answer:

The Answer is One :)

You might be interested in
Help need the answer quick
Shalnov [3]

Answer:

1A

2H

3D

4C

5G

6E hope this helps

6 0
3 years ago
Find the area of the shaded region. Round your answer to the nearest tenth if needed.<br><br> 4B
AlexFokin [52]

Answer:

136.1 inches

Step-by-step explanation:

area of a circle is r^2 x pi

this is 3/4 of a circle

1. so 3/4 x 7.6^2xpi

2. 3/4 x 57.76 x pi

3. .75 x 57.76 x pi

4. 136.1

5 0
3 years ago
What is -2 = 5 / (2x+3)
LUCKY_DIMON [66]

Answer:

x = -11/4

Step-by-step explanation:

Given that:

-2 = 5 / (2x+3)

Multiplying both sides by (2x + 3)

-2(2x + 3) = 5

"-" sign will alter the inner signs

-4x -6 = 5

Adding 6 on both sides:

-4x -6 +6 = 5 + 6

-4x  = 11

Dividing both sides by -4

-4x/-4 = 11/-4

x = -11/4

i hope it will help you!

3 0
3 years ago
An open rectangular box with square base has a volume of 256 cubic inches. determine the equation for the volume and surface are
Serjik [45]
Let
b-----------> the length side of the square box
h------------> the height of the box
SA---------> surface area of the box

we know that
[volume of the box]=b²*h
volume=256 in³
b²*h=256-------> h=256/b²-----> equation 1

surface area of the box=area of the base+perimeter of base*height

area of the base=b²
perimeter of the base=4*b

surface area=b²+(4*b)*h------> SA=b²+4*b*h-----> equation 2

substitute equation 1 in equation 2
SA=b²+4*b*[256/b²]-----> SA=b²+1024/b-----> SA=(b³+1024)/b

the answer is

the formula of the volume of the box is  V=b²*h-----> 256=b²*h

the formula of the surface area of the box are
SA=b²+4*b*h
SA=(b³+1024)/b
4 0
3 years ago
Write an equation of the line below.
Dafna11 [192]

Answer:

\large\boxed{y=4x+3}

Step-by-step explanation:

The slope-intercept form of an equation of aline:

y=mx+b

<em>m</em><em> - slope</em>

<em>b</em><em> - y-intercept</em>

The formula of a slope:

m=\dfraxc{y_2-y_1}{x_2-x_1}

From the graph we have the points:

(-2, -5)

y-intercept (0, 3) → <em>b = 3</em>

Calculate the slope:

m=\dfrac{3-(-5)}{0-(-2)}=\dfrac{8}{2}=4

Put the value of the slope and the y-intercept to the equation of a line:

y=4x+3

3 0
3 years ago
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