Let's recall that I = Prt
so... hmm we're assuming here, it doesn't say there, but this is for 1 year period.
ok... so... let's use two quantities for such interest, say "a" is the Interest for the Principal of 6000, and let's use "b" is the Interest for the Principal of 13000.
![\bf \qquad \textit{Simple Interest Earned}\\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\\ P=\textit{original amount deposited}\to& \$6000\\ r=rate\to r\%\to& \frac{r}{100}\\ t=years\to &1 \end{cases} \\\\\\ a=6000\left( \frac{r}{100} \right)1\implies \stackrel{\textit{P=6000}}{a=60r}\\\\ -------------------------------\\\\](https://tex.z-dn.net/?f=%5Cbf%20%5Cqquad%20%5Ctextit%7BSimple%20Interest%20Earned%7D%5C%5C%5C%5C%0AI%20%3D%20Prt%5Cqquad%20%0A%5Cbegin%7Bcases%7D%0AI%3D%5Ctextit%7Binterest%20earned%7D%5C%5C%0AP%3D%5Ctextit%7Boriginal%20amount%20deposited%7D%5Cto%26%20%5C%246000%5C%5C%0Ar%3Drate%5Cto%20r%5C%25%5Cto%26%20%5Cfrac%7Br%7D%7B100%7D%5C%5C%0At%3Dyears%5Cto%20%261%0A%5Cend%7Bcases%7D%0A%5C%5C%5C%5C%5C%5C%0Aa%3D6000%5Cleft%28%20%5Cfrac%7Br%7D%7B100%7D%20%5Cright%291%5Cimplies%20%5Cstackrel%7B%5Ctextit%7BP%3D6000%7D%7D%7Ba%3D60r%7D%5C%5C%5C%5C%0A-------------------------------%5C%5C%5C%5C)
![\bf \qquad \textit{Simple Interest Earned}\\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\\ P=\textit{original amount deposited}\to& \$13000\\ r=rate\to (r-1)\%\to &\frac{r-1}{100}\\ t=years\to &1 \end{cases} \\\\\\ b=13000\left( \frac{r-1}{100} \right)1\implies \stackrel{\textit{P=13000}}{b=130(r-1)}](https://tex.z-dn.net/?f=%5Cbf%20%5Cqquad%20%5Ctextit%7BSimple%20Interest%20Earned%7D%5C%5C%5C%5C%0AI%20%3D%20Prt%5Cqquad%20%0A%5Cbegin%7Bcases%7D%0AI%3D%5Ctextit%7Binterest%20earned%7D%5C%5C%0AP%3D%5Ctextit%7Boriginal%20amount%20deposited%7D%5Cto%26%20%5C%2413000%5C%5C%0Ar%3Drate%5Cto%20%28r-1%29%5C%25%5Cto%20%26%5Cfrac%7Br-1%7D%7B100%7D%5C%5C%0At%3Dyears%5Cto%20%261%0A%5Cend%7Bcases%7D%0A%5C%5C%5C%5C%5C%5C%0Ab%3D13000%5Cleft%28%20%5Cfrac%7Br-1%7D%7B100%7D%20%5Cright%291%5Cimplies%20%5Cstackrel%7B%5Ctextit%7BP%3D13000%7D%7D%7Bb%3D130%28r-1%29%7D)
now, we know that, whatever the interest amount of "a" is, is 220
less than whatever "b" is.
we know what "b" is,
b = 130(r-1), and 220 less than that is just b - 220, or
130(r-1) - 220.
Answer:
1/4-3x
Step-by-step explanation:
Please mark brainliest.
Answer:
7x -14 = jl
Step-by-step explanation:
Assuming a straight line
jm+ ml = jl
5x-8 + 2x-6 = jl
Combine like terms
7x -14 = jl
Answer:
m∠3 = 24°
Step-by-step explanation:
By the theorem,
"Intercepted arc measures the double of the inscribed angle formed by two chords meeting at one point of the circle."
In the given picture,
∠3 is the inscribed angle subtended by the arc ED and is the intercepted arc.
Therefore, m∠3 = ![\frac{1}{2}m(\text{arc}ED)](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7Dm%28%5Ctext%7Barc%7DED%29)
m∠3 = ![\frac{1}{2}(48)](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%2848%29)
= 24°
Measure of angle 3 is 24 degrees.