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3 years ago

What is the shape of the following distribution?

2 answers:

8 0

we are given the data from 9 to 20. we can plot the data in bar graph. The mean of the data is 15. in this case, we plot the number in x and y in terms of frequency. We can see that the plot is evenly distributed at 15 and then also at the extremes. Hence the answer to this problem is C. symmetric

inna [77]3 years ago

3 0

Answer: C). symmetric

Step-by-step explanation:

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What is X-y=-1 written in y=mx+b form?

exis [7]

Answer:

y = x + 1

Step-by-step explanation:

8 0

3 years ago

a pool shaped like a rectangle prism is 40 feet long, 20 feet wide, and 4 deep. attached to the side of the pool is a hot tub wi

lubasha [3.4K]

Lets start with finding the volume of the pool

The formula for the volume of a rectangular prism is

V=l*w*h where l=length w=width and h=height
plug in the data we know
V=40*20*4
V=3200ft³

Now for the hot tub.

3200ft³*1/4=800ft³

Add the volumes together
3200+800=4000ft³

Answer=4000ft³

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3 years ago

Calculate 0.82 + 0.35 and get the sum of the equation

xz_007 [3.2K]

1.17

because

0.82

0.35 +

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1.17

8 0

3 years ago

Given: I is the midpoint of ME and SL

ANEK [815]

Answer:

SAS

Step-by-step explanation:

Is there multiple answers?

5 0

3 years ago

Read 2 more answers

The U.S. Fish and Wildlife Service reported that the mean length of six-year-old rainbow trout in the Arolik River in Alaska is

Anettt [7]

Answer:

The size limit for 15% of of six-year-old trout is 438.52 mm.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 481 millimeters

Standard Deviation, σ = 41 millimeters

We are given that the distribution of mean length of six-year-old rainbow trout is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

We have to find the value of x such that the probability is 0.15

$P( X < x) = P( z < \displaystyle\frac{x - 481}{41})=0.15$

Calculation the value from standard normal z table, we have,

$\displaystyle\frac{x - 481}{41} = -1.036\\\\x = 438.524$

Thus, the size limit for 15% of of six-year-old trout is 438.52 mm.

5 0

3 years ago