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3 years ago

What is the volume of this right triangular pyramid?

Mathematics

1 answer:

Nady [450]3 years ago

4 0

The volume of a triangular pyramid can be found using the formula V = 1/3AH where A = area of the triangle base, and H = height of the pyramid or the distance from the pyramid's base to the

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Please help! Do you know the answer<br>

azamat

Answer:

x = 9

Step-by-step explanation:

y = 2/3x - 6

If the y point is 0, then plug that number into the equation and solve for x.

0 = 2/3x - 6

Add 6 to both sides of the equation.

6 + 0 = 2/3x - 6 + 6 or 6 = 2/3x

Multiply both sides by 3.

3 x 6 = 2/3x x 3 or 18 = 2x

Divide both sides by 2

18/2 = 2x / 2 or 9 = x

5 0

2 years ago

Decribe how the graph of g(x)= 3/x-4+5 is a translation of g(x)=3/x

ruslelena [56]

-4 next to x value means the graph is moved 4 units to the right
+5 on the end of the function means the graph is moved up 5 units

3 0

3 years ago

Are same side interior angles congruent?

Fed [463]

Same side interior angles are not always congruent

6 0

3 years ago

Read 2 more answers

Solve<br> x2 - 8x + 14 = 2x - 7

BabaBlast [244]

Answer:

x=7, x=3

Step-by-step explanation:

$x^{2} -8x+14=2x-7$

$x^{2} -8x-2x+14+7=0$

$x^{2} -10x+21=0$

$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}$

$x=$ $\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

positive

$x=\frac{-\left(-10\right)+\sqrt{\left(-10\right)^2-4\cdot \:1\cdot \:21}}{2\cdot \:1}$

$x=7$

negative

$x=\frac{-\left(-10\right)-\sqrt{\left(-10\right)^2-4\cdot \:1\cdot \:21}}{2\cdot \:1}$

$x=3$

7 0

3 years ago

19810 rounded to the nearest hundred

Cloud [144]

19,810 rounded to the nearest hundred is 19,800.
8 is in the hundreds place, and the number 1 is in front of it.

Numbers 1-4 in front of the number make the number stay the same.

Numbers 5-9 in front of the number make the numbers round up one number.

3 0

2 years ago

Read 2 more answers