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3 years ago

What is the volume of this right triangular pyramid?

Mathematics

1 answer:

Nady [450]3 years ago

4 0

The volume of a triangular pyramid can be found using the formula V = 1/3AH where A = area of the triangle base, and H = height of the pyramid or the distance from the pyramid's base to the

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What is the solution of this system of linear equations?

creativ13 [48]

Answer: D

Step-by-step explanation:

Consider the first equation. Subtract 3x from both sides.

y−3x=−2

Consider the second equation. Subtract x from both sides.

y−2−x=0

Add 2 to both sides. Anything plus zero gives itself.

y−x=2

To solve a pair of equations using substitution, first solve one of the equations for one of the variables. Then substitute the result for that variable in the other equation.

y−3x=−2,y−x=2

Choose one of the equations and solve it for y by isolating y on the left hand side of the equal sign.

y−3x=−2

Add 3x to both sides of the equation.

y=3x−2

Substitute 3x−2 for y in the other equation, y−x=2.

3x−2−x=2

Add 3x to −x.

2x−2=2

Add 2 to both sides of the equation.

2x=4

Divide both sides by 2.

x=2

Substitute 2 for x in y=3x−2. Because the resulting equation contains only one variable, you can solve for y directly.

y=3×2−2

Multiply 3 times 2.

y=6−2

Add −2 to 6.

y=4

The system is now solved.

y=4,x=2

6 0

2 years ago

Read 2 more answers

Whoever answers this NOW will get brainliest

gavmur [86]

Answer:

I think is -x + 105/42y

Step-by-step explanation:

2(3/10)x - 5/7y - 4(5/6)y - 2(4/5)x

6/10x - 5/7y - 20/6y - 8/5x

6/10x - 8/5x - 5/7y - 20/6y

6-16/10x - 35+140/42y

-10/10x + 105/42y

-x + 105/42y

5 0

3 years ago

How do I calculate the volume of this prism?

Tom [10]

You just multiply them

4 0

2 years ago

The unshaded area inside the figure to the right is 648 in.² Use this fact to write an equation involving x. Then solve the equa

FrozenT [24]

The second order polynomial that involves the variable x (border inside the rectangle) and associated to the unshaded area is x² - 62 · x + 232 = 0.

<h3>How to derive an expression for the area of an unshaded region of a rectangle</h3>

The area of a rectangle (A), in square inches, is equal to the product of its width (w), in inches, and its height (h), in inches. According to the figure, we have two proportional rectangles and we need to derive an expression that describes the value of the unshaded area.

If we know that A = 648 in², w = 22 - x and h = 40 - x, then the expression is derived below:

A = w · h

(22 - x) · (40 - x) = 648

40 · (22 - x) - x · (22 - x) = 648

880 - 40 · x - 22 · x + x² = 648

x² - 62 · x + 232 = 0

The second order polynomial that involves the variable x (border inside the rectangle) and associated to the unshaded area is x² - 62 · x + 232 = 0. $\blacksquare$