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3 years ago

When do we need to consider amounts that do not represent whole numbers?

Mathematics

1 answer:

Alexandra [31]3 years ago

4 0

When we are dealing with fractions and decimals.

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Write an equation of the line that passes through point (2,-4) and has the slope m= 1/2 <br> y =

iren2701 [21]

Answer:

tHe can discuss intelligently the current political affairs. Television is a machine that ought to be used intelligently. It is necessary to think intelligently before performing any action.

Step-by-step explanation:

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2 years ago

Give correct answer and I will give you branlist

tia_tia [17]

Hello!

Space = 5 cm + 10cm + 10cm + 20cm + 22cm + 30cm => space = 15cm + 10cm + 20cm + 22cm + 30cm => space = 25cm + 20cm + 22cm + 30cm => space = 45cm + 22cm + 30cm => space = 67cm + 30cm => space = 97cm²

Good luck! :)

3 0

3 years ago

Read 2 more answers

Assume that the weights of quarters are normally distributed with a mean of 5.67 g and a standard deviation of 0.07 g. If a vend

Black_prince [1.1K]

Answer:

0.98046

Step-by-step explanation:

Given:

μ = 5.67

σ = 0.07

Here we are required to find

P(5.48 <X<5.82) and between 5.48 and 5.82 we each z-score given by

So 5.48 we have z = -2.714 and 5.82 we have z = 2.143

Therefore we have the area of interest on the normal distribution chart given by :

P( -2,714 < z < 2.143)

= 1 - P(Z<-2.714) + P(Z > 2.143)

= 1 - P(Z<-2.714) + (1 - P(Z < 2.143))

= 1 - 0.00336 + 1 - 0.98382

= 1 - 0.01954 = 0.98046

6 0

3 years ago

Read 2 more answers

Times for an ambulance to respond to a medical emergency in a certain town are normally distributed with a mean of 450 seconds a

Gnoma [55]

Answer:

(D)109

Step-by-step explanation:

Mean = 450 seconds

Standard deviation = 50

First, we determine the probability that the expected response time is between 400 seconds and 500 seconds, P(400<x<500)

Using the Z-Score,

$P(\frac{x-\mu}{\sigma}$

From the Z-Score table

P(-1<x<1) = 0.68269

The probability that the expected response time is between 400 seconds and 500 seconds is 0.68269.

Since there are 160 Emergencies

Number whose expected time is between 400 seconds and 500 seconds

$=160 X 0.68269 \approx 109$

6 0

3 years ago

A group of scientists are studying a new species of insects. They observe the patterns of 6 insects. The scientists find that th

Stels [109]

Answer:

(B) $477=6(1+0.20)^t$

Step-by-step explanation:

we can use formula

$P(t)=P_0(1+r)^t$

where

Po is the initial population

r is the growth rate

t is the time in months

We are given

initial population of insects

so, Po=6

The scientists find that the insect population, x, is growing exponentially 20% per month

so, r=0.20

now, we can plug these values

$P(t)=6(1+0.20)^t$

there to be a population of 477 insects

so, P(t)=477

now, we plug it

and we get

$477=6(1+0.20)^t$

4 0

3 years ago