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Aliun [14]
3 years ago
15

I really need help with this

Mathematics
1 answer:
LuckyWell [14K]3 years ago
8 0

Answer:

photo math

Step-by-step explanation:

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After 4 years 4+x=6+1/2x
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Find the 16th term to the series PLEASEEE
slavikrds [6]

Answer:

It is a geometric sequence.

common \ ratio , r = \frac{12}{-4}=-3

a_n = a_1 \times r^{n-1} \\n = 16\\r = -3\\a_1 = -4\\a_{16 }= -4 \times (-3)^{15} = -4 \times 14348907 =57395628

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Solve the equation 3 x+5 y=16 for y
Liono4ka [1.6K]

Answer:

Y = (16 - 3x)/5

Step-by-step explanation:

3x + 5y = 16

subtract 3x from both sides:

16-3x = 5y

divide both sides by 5:

(16 - 3x) / 5 = y

hope this helps

8 0
3 years ago
Find an equation of the tangent line to the hyperbola: x^2/a^2 - y^2/b^2 = 1 at the point (x0,x1)
musickatia [10]

The standard form of a hyperbola is <span><span><span>x2/</span><span>a2 </span></span>− y<span><span>2/ </span><span>b2 = 1
the tangent line is the first derivative of the function</span></span></span><span>y′ = <span>b^2x/ a^2 y
hence the slope is </span></span><span>m = <span>b^2 x0 / <span>a^2 <span>x1

</span></span></span></span>Therefore the equation of the tangent line isy−x1 = b^2 x0 / a^2 x1* (x−x0)

8 0
3 years ago
Beverage A and Beverage B are sold in identical cans. Beverage A is 6% sugar. The portion of Beverage B that is sugar is 0.21. H
muminat

Answer:

3.5 more times sugar in B

Step-by-step explanation:

We need to see that the fact that Beverage B is 0.21 sugar can be translated to percentages, just by multiplying and dividing by 100 to get it easier to see:

0.21 * 100 /100 =  21/100 = 21% percent

This means that for every 100 units, 21 are sugar.

Now we can compare percentages directly, as both have the same volume because are sold in identical cans. We need to get how many times is 21 greater than 6. The only thing we need to do is the ratio between them:

21/6= 3.5

This implies that 21 is 3.5 greater than 6, you can verify it by multiplying 6 by 3.5 and getting 21.

So, B has 3.5 times more sugar than A.

5 0
3 years ago
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