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vazorg [7]
3 years ago
14

Find the missing triagel

Mathematics
1 answer:
MrMuchimi3 years ago
3 0

Answer:

b = 8.9

Step-by-step explanation:

( 12^2 - 8^2 )

(144 - 64)

\sqrt{80}

b= 8.9

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Jay and blair were fishing. Togther,they caught 21 fish. Jay caught 2 times as many fish as blair how many fish did Jay and Blai
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Jay caught 14 and Blair caught 7!
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Solve through substitution<br><br> –3x–8y=20<br><br> y=5x+19<br><br> Point of intersection, please
Sedaia [141]

Answer:

(-4, -1)

Step-by-step explanation:

-3x - 8y = 20; y = 5x + 19

y = 5x + 19; -3x - 8y = 20

y = 5x + 19

-3x - 8y = 20

-3x - 8(5x + 19) = 20

-43x - 152 = 20

-43x - 152 + 152 = 20 + 152

-43x = 172

-43x / -43 = 172 / -43

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Step-by-step explanation:

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A plan for a park has a rectangular plot of wild flowers that needs to be enclosed by 54 feet of fencing. Only three sides need
Gekata [30.6K]

SOLUTION:

Step 1:

In this question, we are given the following:

Step 2:

a) What is the largest area possible for the garden?

Now, let the length of the rectangular plot be 54 -2x,

and the width of the rectangular plot be x,

so that:

\begin{gathered} \text{Area = (54 -2x) x = 54 x -2x}^2 \\ \frac{dA}{dx}=\text{ 54 - 4x = 0} \\ We\text{ have that:} \\ 54\text{ = 4x } \\ \text{Divide both sides by 4, we have that:} \\ \text{x = }\frac{54}{4} \\ \text{x = 13. 5} \end{gathered}

Then, the largest area possible for the garden will be:

\text{Area = 54x -2x}^2=54(13.5)-2(13.5)^2=729-364.5=364.5ft^2

b) What width will produce the maximum area?

Width,\text{ x = 13. 5 fe}et

c) The length of the garden that will produce the maximum area:

\text{Length = 54 - 2x = 54 - 2( 13. 5) = 54 -27 = 27 fe}et

5 0
1 year ago
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