All categories

3 years ago

Find the area of a circle with a diameter= 6.8cm

Mathematics

1 answer:

ale4655 [162]3 years ago

5 0

Answer: 36.32

Step-by-step explanation:

Area of circle is π(r^2)

r is d/2

= 3.14*((6.8/2)^2)

=36.32

You might be interested in

Please help me solve this problem

Maksim231197 [3]

Answer:

i think the answer is 58

but i'm not sure....

check it again with someone else ...

Step-by-step explanation:

90+32=122

180-122=58

4 0

3 years ago

Point M is the midpoint of segment QR. If QM = 16 + x and MR = 2(x + 2), find the length of QM.

pav-90 [236]

Just add them
QM+MR=QR
16+x+2(x+2)=QR
16+x+2x+4=QR
20+3x=QR

6 0

2 years ago

HELP NEEDED ASAP!! Would it be 28.07 or 28 when its says type numerical answer only.

Marizza181 [45]

I think it would be 28

5 0

3 years ago

PLEASE HELP, ITS TIMED SO HURRY PLEASE>>>>>>>

Olegator [25]

Answer:

The answer is noncollinear

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

1+secA/sec A = sin^2 A / 1-cos A

Fofino [41]

Answer: see proof below

Step-by-step explanation:

$\dfrac{1+\sec A}{\sec A}=\dfrac{\sin^2 A}{1-\cos A}$

Use the following Identities:

sec Ф = 1/cos Ф

cos² Ф + sin² Ф = 1

Proof LHS → RHS

$\text{LHS:}\qquad \qquad \dfrac{1+\sec A}{\sec A}$

$\text{Identity:}\qquad \qquad \dfrac{1+\frac{1}{\cos A}}{\frac{1}{\cos A}}$

$\text{Simplify:}\qquad \qquad \dfrac{\frac{\cos A+1}{\cos A}}{\frac{1}{\cos A}}\\\\\\.\qquad \qquad \qquad =\dfrac{1+\cos A}{1}$

$\text{Multiply:}\qquad \qquad \dfrac{1+\cos A}{1}\cdot \bigg(\dfrac{1-\cos A}{1-\cos A}\bigg)\\\\\\.\qquad \qquad \qquad =\dfrac{1-\cos^2 A}{1-\cos A}$

$\text{Identity:}\qquad \qquad \dfrac{\sin^2 A}{1-\cos A}$

$\text{LHS = RHS:}\quad \dfrac{\sin^2 A}{1-\cos A}=\dfrac{\sin^2 A}{1-\cos A}\quad \checkmark$

3 0

3 years ago