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3 years ago

What is the greatest common factor GCF of 10 and four

Mathematics

2 answers:

Feliz [49]3 years ago

7 0

Answer:

Step-by-step explanation:

thats the biggest number that goes with both

Pani-rosa [81]3 years ago

3 0

Answer:

Take the numbers 50 and 30. Their greatest common factor is 10, since 10 is the greatest factor that both numbers have in common. To find the GCF of greater numbers, you can factor each number to find their prime factors, identify the prime factors they have in common, and then multiply those together.

Step-by-step explanation:

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How can you tell when the LCM of two numbers will equal one of the numbers or equal the product of the numbers

Vladimir79 [104]

When one number will divide exactly into the other one then the other one will be the LCM. For example the LCM of 4 and 8 = 8 .

When they do not divide as above then the product of the numbers may be the LCM. For example the LCM of 3 and 4 = 3*4 = 12.

The product is not always the LCM. It might be a lower number . For example the LCM of 4 and 6 is not 24 but 12. ( 24 / 2).

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3 years ago

4x-5x+7-9y+2x+34<br> (Simply)

Studentka2010 [4]

I believe it is 1x - 9y + 41

5 0

3 years ago

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Find the value of x. Please help

Doss [256]

Answer:

Step-by-step explanation:

height of the hypotenuse:

$\sqrt{60^2-36^2} = \sqrt{3600 - 1296} = \sqrt{2304} = 48$

36 : height = height : x

36 : 48 = 48 : x

x= 48^2/36 = 64

7 0

3 years ago

Read 2 more answers

Use the given information to find the exact value of the trigonometric function

eimsori [14]

$\begin{gathered} \csc \theta=-\frac{6}{5} \\ \tan \theta>0 \\ \cos \frac{\theta}{2}=\text{?} \end{gathered}$

Half Angle Formula

$\cos \frac{\theta}{2}=\pm\sqrt[\square]{\frac{1+\cos\theta}{2}}$ $\tan \theta>0\text{ and csc}\theta\text{ is negative in the third quadrant}$ $\begin{gathered} \csc \theta=-\frac{6}{5}=\frac{r}{y} \\ x^2+y^2=r^2 \\ x=\pm\sqrt[\square]{r^2-y^2} \\ x=\pm\sqrt[\square]{6^2-(-5)^2} \\ x=\pm\sqrt[\square]{36-25} \\ x=\pm\sqrt[\square]{11} \\ \text{x is negative since the angle is on the 3rd quadrant} \end{gathered}$ $\begin{gathered} \cos \theta=\frac{x}{r}=\frac{-\sqrt[\square]{11}}{6} \\ \cos \frac{\theta}{2}=\pm\sqrt[\square]{\frac{1+\cos\theta}{2}} \\ \cos \frac{\theta}{2}is\text{ also negative in the 3rd quadrant} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{1+\frac{-\sqrt[\square]{11}}{6}}{2}} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{\frac{6-\sqrt[\square]{11}}{6}}{2}} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}} \\ \\ \end{gathered}$

Answer:

$\cos \frac{\theta}{2}=-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}}$

Checking:

$\begin{gathered} \frac{\theta}{2}=\cos ^{-1}(-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}}) \\ \frac{\theta}{2}=118.22^{\circ} \\ \theta=236.44^{\circ}\text{ (3rd quadrant)} \end{gathered}$

Also,

$\csc \theta=\frac{1}{\sin\theta}=\frac{1}{\sin (236.44)}=-\frac{6}{5}\text{ QED}$

The answer is none of the choices

7 0

1 year ago

Angelo thinks of a number, multiplies it by 5 and subtracts 8.His number is 47,wite as an equation in y and solve to find Angelo

Inessa05 [86]

Answer:

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3 years ago