Answer:
option c is correct that is 32
Explanation:
meiosis occur in two phases in the first phase DNA replication occur and amount of DNA becomes doubled without any changes in the chromosomes number and two daughter cells( each 2n) are formed
now in stage 2 each daughter cell undergoes mitosis with the formation of two cells each with half chromosomes (n)
now 2n =32
n=32/2=16
after meiosis stage 1 ........ two daughter cell each with 32 chromosomes
stage 2.... each daughter cell form two grand daughter cell each with 16 chromosomes
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I believe it's B. That would be the best guess
Answer:
B. 0.42
Explanation:
Since the two alleles are at Hardy-Weinberg equilibrium, the sum of the frequency of two alleles will be one. If the frequency of a dominant allele is "p" and that of the recessive allele is "q", then p+q=1
According to the given information, the frequency of one allele in the population is= 0.7
This means that the frequency of the other allele would be= 1-0.7 = 0.3
Frequency of heterozygote in the population =2pq = 2 x 0.7 x 0.3 = 0.42
