Probability that the child would be homozygous for the g542x allele 0.00
<h3>why the probability is nil?
</h3>
- The kid cannot be homozygous for the G542X gene since only the mother has it; the father, on the other hand, has a mutant dF508 allele and so cannot pass on a copy of mutant G542X = never homozygous recessive child.
- A kid must have the G542X allele from both parents in order to be homozygous for the G542X allele. Because only the mother possesses the G542X gene, the child's chances of being homozygous for the G542X allele are 0.00
<h3>
When offspring show a blend of the parents traits one allele is dominant over the other?</h3>
- At the point when one allele is predominant over another, posterity show a mix of guardians' qualities.
- The heterozygous aggregate in complete predominance is tracked in the middle of between two homozygous aggregates. A heterozygous individual showcases qualities of the two guardians in the event of codominance.
To learn more about hetrozygous from the given link
brainly.com/question/1626661
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Answer:
Hello! Sorry i am late! Here is my best answer below.
Fertilization happens when a sperm cell successfully <u>meets an egg cell in the fallopian tube.</u> Once fertilization takes place, this newly fertilized cell is called a <u>zygote.</u> From here, the zygote will move <u>down the fallopian tube</u> and <u>into the uterus</u>. The zygote then <u>burrows</u> into the <u>uterus lining</u>.
Explanation:
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Answer: bacterial species of the genera Staphylococcus, Streptococcus, Enterococcus, Klebsiella, Enterobacter, and Neisseria.
Explanation:
To find the average number of cell cultured per area, you have to divide the total cell count with the total area. The cultured cells contains 7 x 10^5 cells count in 50 ml of medium area. The number would be: 7 x 10^5 cells / 50ml= 0.14x 10^5 cells /ml= 1.4 x 10^4 cells/ml
