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3 years ago

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According to this site, if you know the coordinates of two points on a line, what form would you use to write the equation of th

e
line? Explain the process for writing the equation. (Site 1)

1 answer:

navik [9.2K]3 years ago

3 0

You would use the POINT SLOPE FORMULA and the Slope Formula

which is as follows ...

slope formula : $\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

point slope formula: $y - y_{1} = m(x - x_{1} )$

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WILL GIVE BRAINLIEST: If the graph of 2x+3y − 6=0 is perpendicular to the graph of ax − 3y=5. What is the value of a?

Ilya [14]

Answer:

a = $\frac{9}{2}$

Step-by-step explanation:

To find the value of a, find the Slope of both the equations.

For lines to be perpendicular to each other $m_{1}m_{2} = - 1$

For line 1:

2x + 3y − 6 = 0 represent the line in y=mx +c form

3y = -2x + 6

y = $\frac{-2}{3} x$ + $\frac{6}{3}$

y = $\frac{-2}{3} x$ + 2

$m_{1}$ = $\frac{-2}{3}$

For line 2:

ax - 3y = 5

ax = 5 + 3y

ax - 5 = 3y

y = $\frac{ax}{3} - \frac{5}{3}$

$m_{2}$ = $\frac{a}{3}$

Apply the condition of perpendicularity:

$\frac{-2}{3}$ * $\frac{a}{3}$ = - 1

$\frac{2a}{9} = 1$

a = $\frac{9}{2}$

7 0

3 years ago

part 3. Find the value of the trig function indicated, use Pythagorean theorem to find the third side if you need it.

Nat2105 [25]

Answer: $\bold{9)\ \sin \theta=\dfrac{1}{3}\qquad 10)\ \sin \theta = \dfrac{4}{5}\qquad 11)\ \cos \theta = \dfrac{\sqrt{11}}{6}\qquad 12)\ \tan \theta = \dfrac{17\sqrt2}{26}}$

<u>Step-by-step explanation:</u>

Pythagorean Theorem is: a² + b² = c² , <em>where "c" is the hypotenuse</em>

<em />

$9)\ \sin \theta=\dfrac{\text{side opposite of}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{4}{12}\quad \rightarrow \large\boxed{\dfrac{1}{3}}$

Note: 4² + (8√2)² = hypotenuse² → hypotenuse = 12

$10)\ \sin \theta=\dfrac{\text{side opposite of}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{16}{20}\quad \rightarrow \large\boxed{\dfrac{4}{5}}$

Note: 12² + opposite² = 20² → opposite = 16

$11)\ \cos \theta=\dfrac{\text{side adjacent to}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{\sqrt{11}}{6}\quad =\large\boxed{\dfrac{\sqrt{11}}{6}}$

Note: adjacent² + 5² = 6² → adjacent = √11

$12)\ \tan \theta=\dfrac{\text{side opposite of}\ \theta}{\text{side adjacent to}\ \theta}=\dfrac{17}{13\sqrt2}\quad =\large\boxed{\dfrac{17\sqrt2}{26}}$

Note: adjacent² + 7² = (13√2)² → adjacent = 17

5 0

3 years ago

If you died with braces on would they take them off?

Lady bird [3.3K]

Answer:

Uhm, I don't think so could you payed for braces or your insurance paid for them.

6 0

2 years ago

Trigonometric equations<br><br> 5sinx = 3sinx + square root of 2

Lera25 [3.4K]

$\qquad\qquad\huge\underline{{\sf Answer}}♪$

Let's solve for x ~

$\qquad \sf \dashrightarrow \:5 \sin(x) = 3 \sin(x) + \sqrt{2}$

$\qquad \sf \dashrightarrow \:5 \sin(x) - 3 \sin(x) = \sqrt{2}$

$\qquad \sf \dashrightarrow \:2 \sin(x) = \sqrt{2}$

$\qquad \sf \dashrightarrow \: \sin(x) = \sqrt{2} \div 2$

$\qquad \sf \dashrightarrow \: \sin(x) = \frac{1}{ \sqrt{2} }$

$\qquad \sf \dashrightarrow \:x = 45 \degree \: \: or \: \: \frac{\pi}{4} \: rad$

・．━━━━━━━†━━━━━━━━━．・

4 0

2 years ago

What is the surface area

ArbitrLikvidat [17]

Answer:

184 m²

Step-by-step explanation:

Surface Area = 2(10*2) + 2(10*6) + 2(2*6)

Surface Area = 2(20 + 60 + 12)

Surface Area = 2(92)

Surface Area = 184 m²

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

5 0

3 years ago