A level chem naming isomers
1 answer:
Answer:
Butan-1-ol or Butanol
2-methylpropan-2-ol
2-methylpropan-1-ol
Butan-2-ol
Explanation:
Data Give:
Three Isomers are given
names of These =?
Details:
Isomers:
Isomers are those chemical compounds that have same molecular formula but different structures.
In the given question the compound have same molecular formula that is C₄H₉OH but the structures are different.
So due to different structures they are named differently.
The 1st and last one are straight Chains and the other 2 are branched. all the structure have four carbon atoms, one OH group and 9 hydrogen atoms.
Names are given in attachment
butan-1-ol or Butanol
As it contain 4 carbon atoms an -OH group is attached at position 1.
________________
2-methylpropan-2-ol
In this -OH and -CH₃ is attached on carbon 2
_____________
2-methylpropan-1-ol
In this -CH₃ attached at position 2 and -OH is attached on Carbon 1.
______________
Butan-2-ol
In this 4 carbons are in straight chain and a -OH group is attached on position 2 of carbon
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The reducing agent in the reaction 2Li(s) + Fe(CH₃COO)₂(aq) → 2LiCH₃COO(aq) + Fe(s) is lithium (Li).
The general reaction is:
2Li(s) + Fe(CH₃COO)₂(aq) → 2LiCH₃COO(aq) + Fe(s) (1)
We can write the above reaction in <u>two reactions</u>, one for oxidation and the other for reduction:
- Oxidation reaction
Li⁰(s) → Li⁺(aq) + e⁻ (2)
- Reduction reaction
Fe²⁺(aq) + 2e⁻ → Fe⁰(s) (3)
We can see that Li⁰ is oxidizing to Li⁺ (by <u>losing</u> one electron) in the lithium acetate (<em>reaction 2</em>) and that Fe²⁺ in iron(II) acetate is reducing to Fe⁰ (by <u>gaining</u> two <em>electrons</em>) (<em>reaction 3</em>).
We must remember that the reducing agent is the one that will be oxidized by <u>reducing another element</u> and that the oxidizing agent is the one that will be reduced by <u>oxidizing another species</u>.
In reaction (1), the<em> reducing agent</em> is <em>Li</em> (it is oxidizing to Li⁺), and the <em>oxidizing agent </em>is<em> Fe(CH₃COO)₂</em> (it is reducing to Fe⁰).
Therefore, the reducing agent in reaction (1) is lithium (Li).
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