A level chem naming isomers
1 answer:
Answer:
Butan-1-ol or Butanol
2-methylpropan-2-ol
2-methylpropan-1-ol
Butan-2-ol
Explanation:
Data Give:
Three Isomers are given
names of These =?
Details:
Isomers:
Isomers are those chemical compounds that have same molecular formula but different structures.
In the given question the compound have same molecular formula that is C₄H₉OH but the structures are different.
So due to different structures they are named differently.
The 1st and last one are straight Chains and the other 2 are branched. all the structure have four carbon atoms, one OH group and 9 hydrogen atoms.
Names are given in attachment
butan-1-ol or Butanol
As it contain 4 carbon atoms an -OH group is attached at position 1.
________________
2-methylpropan-2-ol
In this -OH and -CH₃ is attached on carbon 2
_____________
2-methylpropan-1-ol
In this -CH₃ attached at position 2 and -OH is attached on Carbon 1.
______________
Butan-2-ol
In this 4 carbons are in straight chain and a -OH group is attached on position 2 of carbon
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Answer:
See Explanation
Explanation:
Hence the mass defect is;
[235.04393 + 1.00867] - [ 136.92532 + 96.91095 + 2(1.00867)]
= 236.0526 - 235.85361
= 0.19899 amu
Since 1 amu = 1.66 * 10^-27 Kg
0.19899 amu = 0.19899 * 1.66 * 10^-27 = 3.3 * 10^-28 Kg
Binding energy = Δmc^2
Binding energy = 3.3 * 10^-28 Kg * (3 * 10^8)^2 = 2.97 * 10^-11 J
ii)
Hence the mass defect is;
[10.01294 + 1.00867] - [7.01600 + 4.00260]
= 11.02161 - 11.0186
= 0.00301 amu
Since 1 amu = 1.66 * 10^-27 Kg
0.00301 amu = 0.00301 * 1.66 * 10^-27 = 4.997 * 10^-30 Kg
Binding energy = Δmc^2
Binding energy = 4.997 * 10^-30 Kg * (3 * 10^8)^2 = 4.5 * 10^-13 J
If I have 0.725 moles of gas at a temperature of 105 K and a pressure of 3.75 atmospheres the volume of the gas 1.66 litres.
Explanation:
Data given:
number of moles of the gas = 0.725
temperature = 105 K
pressure = 3.75 atm
volume of the gas =?
R = 0.08206 Latm/mole Kelvin
Applying the ideal gas law to calculate the volume of the given gas:
PV = nRT
rearranging the equation to calculate volume:
V =
putting the values in the equation:
V =
V = 1.66 Litres.
At a temperature of 105 K and pressure of 3.75 atm, 0.725 moles of gas occupy 1.66 litres of volume.