1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ddd [48]
3 years ago
9

How are minute and seconds are related to degrees

Chemistry
2 answers:
jekas [21]3 years ago
5 0

These minutes are further divided into sixty parts called seconds. The words minute and second used in this context have no immediate connection to how those words are usually used as amounts of time. In a full circle there are 360 degrees. Each degree is split up into 60 parts, each part being 1/60 of a degree.

No then contact me about that

riadik2000 [5.3K]3 years ago
5 0

Answer:

These minutes are further divided into sixty parts called seconds. The words minute and second used in this context have no immediate connection to how those words are usually used as amounts of time. In a full circle there are 360 degrees. Each degree is split up into 60 parts, each part being 1/60 of a degree.

Explanation:

You might be interested in
6020000 in scientific notation
kobusy [5.1K]
6.02 x 10^6

Hoped that helped.
7 0
3 years ago
When people walked on the Moon, they found that they could jump higher than they could back on Earth. Why is this true?
Allushta [10]

Answer: B

Explanation: the moon is smaller and contains less mass, therefore its gravitational pull is less than that of Earth's.

8 0
3 years ago
Describe what happens to the mass number and the atomic number of a nuclide during alpha decay.
Digiron [165]

Answer:

The answer to your question is: The mass number will be 4 units lower.

Explanation:

Alpha particles are Helium atoms, which have a mass number of 4 and atomic number of 2.

When an alpha particle is released, the original atom loses 2 protons and and 2 neutrons an we can see in the example.

                             ²²⁶ ₈₈ Ra  ⇒   ²²² ₈₆ Rn   +   ⁴₂ He

3 0
3 years ago
Read 2 more answers
I will give the first person brainliest! please helppp
Murrr4er [49]

okay so the  Answer is c

7 0
3 years ago
If the reactants have a potential energy of 10.2 kJ/mol and the products have a potential
Citrus2011 [14]

Answer:

The ΔH is 5.5 kJ/mol and the reaction is endothermic.

Explanation:

To calculate the ∆H (heat of reaction) of the combustion reaction, that is, the heat that accompanies the entire reaction, you must make the total sum of all the heats of the products and of the reagents affected by their stoichiometric coefficient ( number of molecules of each compound participating in the reaction) and finally subtract them:

Combustion enthalpy = ΔH = ∑H products - ∑Hreactants

In this case:

ΔH = 15.7 kJ/mol - 10.2 kJ/mol= 5.5 kJ/mol

An endothermic reaction is one whose enthalpy value is positive, that is, the system absorbs heat from the environment (ΔH> 0).

<u><em>The ΔH is 5.5 kJ/mol and the reaction is endothermic.</em></u>

4 0
3 years ago
Other questions:
  • A patient needs to take her cholesterol medication every morning and night. Her prescription bottle most likely says
    12·1 answer
  • A loose, icy body with a long, narrow orbit is?
    12·2 answers
  • Brain, Spinal Cord
    15·2 answers
  • What is an output force?
    13·2 answers
  • Which of these elements exhibits chemical behavior similar to that of oxygen? select one:
    14·1 answer
  • . Given the reaction 2HgO → 2Hg + O2 , how many moles of elemental mercury will be obtained by the decomposition of 1 mole of Hg
    14·1 answer
  • Classify these molecules as polar or nonpolar. Drag each item to the appropriate bin.
    13·1 answer
  • Which data table below correctly describes the parts of an atom?
    9·1 answer
  • amount of energy released, which is represented by the ccc Energy and Matter the surface of the sun is at a temperature of about
    5·1 answer
  • Science
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!