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2 years ago

Find the distance of the line segment joining the two points (5, 4) and (−2, 1)

Mathematics

1 answer:

Scilla [17]2 years ago

3 0

Distance formula... but the answer is square root of 58 units with is approximately 7.61577

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Can anyone help me wit this!!

dybincka [34]

Answer:

See attachment for table values
y₁ = y₂ for x = 6

Step-by-step explanation:

In each case, put the x-value in the formula and do the arithmetic. If you're allowed, you can save some time and effort by realizing that the solution (x) will have to be an even number.

y₁ is an integer value for all integer values of x. y₂ is an integer value for even values of x only. y₁ and y₂ will both be integers (and possibly equal) only when x is even.

For example, for x = 6, we have

... y₁ = 3·6 - 8 = 18 -8 = 10

... y₂ = 0.5·6 +7 = 3 +7 = 10

That is, for x = 6, both columns of the table have the same number (10). That is, y₁ = y₂ for x = 6. The solution to the equation

... y₁ = y₂

... x = 6.

3 0

3 years ago

5.7 as an improper fraction

harkovskaia [24]

Answer:

5.7 = $\frac{57}{10}$ as an improper fraction

Step-by-step explanation:

When dividing a number by 10 the decimal moves one place to the left. When we take 57 and divide it by 10, we get 5.7

5 0

3 years ago

Drag each relation to the correct location on the table.

asambeis [7]

So what is the question exactly I’m confused on how this is asked

5 0

3 years ago

Read 2 more answers

Which point would be a solution to the system of linear inequalities ?

brilliants [131]

Answer:

(12,-6)

Step-by-step explanation:

we have

$y\leq \frac{4}{3}x+5$ ----> inequality A

$y\geq -\frac{5}{2}x+5$ ---> inequality B

we know that

If a ordered pair is a solution of the system of inequalities, then the ordered pair must satisfy both inequalities (makes true both inequalities)

<u><em>Verify each point</em></u>

Substitute the value of x and the value of y of each ordered pair in the inequality A and in the inequality B

case 1) (0,-1)

Inequality A

$-1\leq \frac{4}{3}(0)+5$

$-1\leq5$ ----> is true

Inequality B

$-1\geq -\frac{5}{2}(0)+5$

$-1\geq 5$ ----> is not true

therefore

The ordered pair is not a solution of the system

case 2) (0,3)

Inequality A

$3\leq \frac{4}{3}(0)+5$

$3\leq5$ ----> is true

Inequality B

$3\geq -\frac{5}{2}(0)+5$

$3\geq 5$ ----> is not true

therefore

The ordered pair is not a solution of the system

case 3) (-6,-6)

Inequality A

$-6\leq \frac{4}{3}(-6)+5$

$-6\leq-3$ ----> is true

Inequality B

$-6\geq -\frac{5}{2}(-6)+5$

$-6\geq 20$ ----> is not true

therefore

The ordered pair is not a solution of the system

case 4) (12,-6)

Inequality A

$-6\leq \frac{4}{3}(12)+5$

$-6\leq21$ ----> is true

Inequality B

$-6\geq -\frac{5}{2}(12)+5$

$-6\geq -25$ ----> is true

therefore

The ordered pair is a solution of the system (makes true both inequalities)

8 0

3 years ago

Bella and Heather put some money into their money boxes every week. The amount of money (y), in dollars, in their money boxes af

Hatshy [7]

Answer:

$\boxed{ \text{B. 10 weeks, \$310 }}\\$

Step-by-step explanation:

We have two conditions:

$\begin{array}{lrcll}(1) & y & = & 25x + 60 & \\(2) & y & = & 30x + 10 & \\ & 25x + 60 & = & 30 x + 10 & \text {Set (1) = (2)} \\ & 50 & = & 5x & \text{Subtracted 25x from each side} \\& x & = & 10 &\text{Divided each side by 5} \\\end{array}\\$ $\\\boxed{ \textbf{The number of weeks is }x = 10}\\$

Bella: y = 25x + 60 = 25(10) + 60 = 250 + 60 = 310

Heather: y = 30x + 10 = 30(10) + 10 = 300 + 10 = 310

7 0

3 years ago