240 degrees is the only one that could not be a value of theta.
10 * 6 = 60 by the time Zach joins so 125-60 = 65
Now 6 (lexie) +7 (zach) = 13 (together) and 65/13 = 5.
6*5 = 30 and 7*5 = 35. 35+30 = 65
Your answer is 5.
Given:
m∠NRQ = 60°
To find:
The angle measure of minor arc NQ
Solution:
The inscribed angle is half of the intercepted arc.
![$\Rightarrow m\angle NRQ =\frac{1}{2} m(ar NQ)](https://tex.z-dn.net/?f=%24%5CRightarrow%20m%5Cangle%20NRQ%20%3D%5Cfrac%7B1%7D%7B2%7D%20m%28ar%20NQ%29)
Multiply by 2 on both sides.
![$\Rightarrow 2 \times m\angle NRQ =2 \times \frac{1}{2} m(ar NQ)](https://tex.z-dn.net/?f=%24%5CRightarrow%202%20%5Ctimes%20m%5Cangle%20NRQ%20%3D2%20%5Ctimes%20%5Cfrac%7B1%7D%7B2%7D%20m%28ar%20NQ%29)
![$\Rightarrow 2 \ m\angle NRQ =m(ar NQ)](https://tex.z-dn.net/?f=%24%5CRightarrow%202%20%5C%20m%5Cangle%20NRQ%20%3Dm%28ar%20NQ%29)
Substitute m∠NRQ = 60°.
![$\Rightarrow 2\times 60^\circ=m(ar NQ)](https://tex.z-dn.net/?f=%24%5CRightarrow%202%5Ctimes%2060%5E%5Ccirc%3Dm%28ar%20NQ%29)
![$\Rightarrow 120^\circ=m(ar NQ)](https://tex.z-dn.net/?f=%24%5CRightarrow%20120%5E%5Ccirc%3Dm%28ar%20NQ%29)
The measure of minor arc NQ is 120°.
Factor the following:x^4 + 4 x^3 + 6 x^2 + 4 x + 1
The coefficients match the 5^th row of Pascal's triangle, so x^4 + 4 x^3 + 6 x^2 + 4 x + 1 = (x + 1)^4:Answer: (x + 1)^4
<u>Answer:</u>
BC = 18 cm
<u>Step-by-step explanation:</u>
As we can see from the diagram:
AB + BC + CD = AD
⇒ 10 cm + BC + 11 cm = 39 cm
⇒ BC + 21 cm = 39 cm
⇒ BC = 39 cm - 21 cm
⇒ BC = 18 cm