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maksim [4K]
3 years ago
9

Find the mean absolute deviation of the set of data. 4, 5, 8, 8, 10 (I also need on this)

Mathematics
1 answer:
Klio2033 [76]3 years ago
3 0

Answer:

MAD = 0

Step-by-step explanation:

When I calculated this by hand I got 0. To find the MAD:

1. You first need to find the mean of the numbers.

4 + 5 + 8 + 8 + 10 = 35

35/5 = 7

the mean value = 7

2. Then you must find the absolute value of the difference between each data value and the mean: |data value – mean|

(4 - 7) = -3

(5 - 7) = -2

(8 - 7) = 1

(8 - 7) = 1

(10 - 7) = 3

3. Add the difference values up

(-3) + (-2) + 1 + 1 +3 = 0

4. Divide the sum of the absolute values of the differences by the number of data values.

0/5 = 0

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Solve the area formula for h
White raven [17]

The answer is C: h = \frac{2A}{b}

Starting with the given formula for the area, A = 1/2hb, the first step is to isolate h by using the multiplicative inverse of b, which is \frac{1}{b} on both sides of the equation:

A(\frac{1}{b})  =  \frac{1}{2}hb* (\frac{1}{b})

The result will be:

\frac{A}{b} = \frac{1}{2}h

The last step is to use the multiplicative inverse of \frac{1}{2}, which is 2 or \frac{2}{1} to further isolate the variable <em>h </em>:

\frac{A}{b} (\frac{2}{1}) = (\frac{2}{1}) \frac{1}{2} h

The formula for h will be:

h = \frac{2A}{b}  which is the option C in your question.

4 0
3 years ago
Is 4/5 less than greater than or equal to 3/4
ryzh [129]
4/5=0.8
3/4=.75
So, 4/5 is greater than 3/4
Hope this helped

8 0
3 years ago
Read 2 more answers
Help Plz Marking Brainliet
emmasim [6.3K]

Answer:

B

Step-by-step explanation:

3 0
3 years ago
Please I need help on these, dosent need to be right.
Pie

Answer:

Plug in the numbers in the table to find the pattern.

Step-by-step explanation:

3 0
3 years ago
Angi has 32 nickels and dimes. Their total value is $1.90. How many of each coin does she have?
Radda [10]

Answer:

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Step-by-step explanation:

The number of nickels is N, and the number of dimes is D.

N + D = 32

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D = 6

N = 26

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3 years ago
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