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Sauron [17]
3 years ago
10

You drive for 30 min at 100 km/h and then stop for 15 min. you then drive for 45 min and 80 km/h. you average speed for the enti

re trip is
Mathematics
1 answer:
Rasek [7]3 years ago
4 0
  <span>So basically you drove 1/2 hour at 100 km/h which works out to a total travel distance of 50 km (you multiply a 1/2 by 100) 

Then you drove for 3/4 hour at 80 Km/h which works out to a total travel distance of 60 km (multiply 3/4 by 80) 

 now you know that you traveled a total of 110 km 

now add up all the times 30 + 15 + 45 = 90 minutes or 1.5 hours 

 now you know that you traveled a total of 110 km in 1.5 hours 

so your average speed is 73.33 km/h for the entire trip</span>
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Determine whether the underlined numerical value is a parameter or a statistic. Explain your reasoning. In a certain soccer leag
Gennadij [26K]

Answer:

Step-by-step explanation:

A Parameter is a value that represents a property of a population. This could be the population mean.

A statistic is a value that represents a property of a sample. This could be the sample mean.

In the given scenario, the population is the entire 14 teams. This means that the percentage given is a value representing a property of the population. Therefore, the correct answer is

C. Parameter, because the data set of all 14 teams is a population.

4 0
3 years ago
Brenda noticed that the reptile building at the zoo was located at the point (-3, 4) on the zoo map. Name the quadrant of the ma
rodikova [14]
It is located in quadrant 2
4 0
2 years ago
-4/5 to the power of 2 times -3/50
Crazy boy [7]
=(-4/5)^2 * -3/50
square -4/5 first; remember -4/5^2 is the same as -4/5 * -4/5

=(-4/5 * -4/5) * -3/50
multiply -4 numerators; multiply 5 denominators

=(-4 * -4)/(5 * 5) * -3/50

=16/25 * -3/50
multiply numerators 16 & -3; multiply denominators 25 & 50

=(16 * -3)/(25 * 50)
= -48/1250

simplify by 2
= -24/625 (or -0.0384)


ANSWER: -24/625 (or -0.0384)

Hope this helps! :)
6 0
3 years ago
Read 2 more answers
(1 point) consider the function f(t)=⎧⎩⎨⎪⎪⎪⎪0,−5,−6,6,t&lt;00≤t&lt;11≤t&lt;7t≥7;f(t)={0,t&lt;0−5,0≤t&lt;1−6,1≤t&lt;76,t≥7; 1. wr
sergij07 [2.7K]
f(t)=\begin{cases}0&\text{for }t

Recall that

u(t)=\begin{cases}0&\text{for }t

Take it one piece at a time. For t\ge0, we can scale u(t) by -5:

-5u(t)=\begin{cases}0&\text{for }t

If we shift the argument by 1 and scale by -5, we have

-5u(t-1)=\begin{cases}0&\text{for }t

so if we subtract this from -5u(t), we'll end up with

-5u(t)+5u(t-1)=\begin{cases}0&\text{for }t

For the next piece, we can add another scaled and shifted step like

-6u(t-1)+6u(t-7)=\begin{cases}0&\text{for }t

so that

-5u(t)+5u(t-1)-6u(t-1)+6u(t-7)=\begin{cases}0&\text{for }t

For the last piece, we add one more term:

6u(t-7)=\begin{cases}0&\text{for }t

and so putting everything together, we get f(t):

f(t)\equiv-5u(t)+5u(t-1)-6u(t-1)+6u(t-7)+6u(t-7)
f(t)\equiv-5u(t)-u(t-1)+12u(t-7)
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3 years ago
Whattt reallyyyyyyyyyy woww
snow_lady [41]

Answer:

oof

Step-by-step explanation:

8 0
2 years ago
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