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Sauron [17]
3 years ago
10

You drive for 30 min at 100 km/h and then stop for 15 min. you then drive for 45 min and 80 km/h. you average speed for the enti

re trip is
Mathematics
1 answer:
Rasek [7]3 years ago
4 0
  <span>So basically you drove 1/2 hour at 100 km/h which works out to a total travel distance of 50 km (you multiply a 1/2 by 100) 

Then you drove for 3/4 hour at 80 Km/h which works out to a total travel distance of 60 km (multiply 3/4 by 80) 

 now you know that you traveled a total of 110 km 

now add up all the times 30 + 15 + 45 = 90 minutes or 1.5 hours 

 now you know that you traveled a total of 110 km in 1.5 hours 

so your average speed is 73.33 km/h for the entire trip</span>
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Please help! Question above
LiRa [457]

Answer:

4

Step-by-step explanation:I just took the quiz

5 0
3 years ago
Alex wants to fence in an area for a dog park. He has plotted three sides of the fenced area at the points E (1, 5), F (3, 5), a
hram777 [196]

Answer:

(1,1)

Step-by-step explanation:

Given: E, F, G, H denote the three coordinates of the area fenced

To find: coordinates of point H

Solution:

According to distance formula,

length of side joining points (x_1,y_1)\,,\,(x_2,y_2) is equal to \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

So,

EF=\sqrt{(3-1)^2+(5-5)^2}=2\,\,units\\FG=\sqrt{(6-3)^2+(1-5)^2}=\sqrt{9+16}=5\,\,units\\GH=\sqrt{(x-6)^2+(y-1)^2}\\EH=\sqrt{(x-1)^2+(y-5)^2}

Perimeter of a figure is the length of its outline.

EF+FG+GH+EH=16\\2+5+\sqrt{(x-6)^2+(y-1)^2}+\sqrt{(x-1)^2+(y-5)^2}=16\\\sqrt{(x-6)^2+(y-1)^2}+\sqrt{(x-1)^2+(y-5)^2}=16-2-5\\\sqrt{(x-6)^2+(y-1)^2}+\sqrt{(x-1)^2+(y-5)^2}=9

Put (x,y)=(1,1)

\sqrt{(1-6)^2+(1-1)^2}+\sqrt{(1-1)^2+(1-5)^2}=9\\\sqrt{25}+\sqrt{16}=9\\5+4=9\\9=9

This is true.

So, the point (1,1) satisfies the equation \sqrt{(x-6)^2+(y-1)^2}+\sqrt{(x-1)^2+(y-5)^2}=9

So, point H is (1,1).

7 0
3 years ago
I need help with this...
lisov135 [29]

   ln 5
e              =    ?
                                    x
Keep in mind that y=e     and y = ln x are inverse functions of one another.
  ln 5
e       ,  we can drop both the "e" and the "ln 5."  We are left with 5 (answer).
                                                                                        ln 5
Alternatively, we could take the ln of both sides of y = e

which will result in ln y = (ln 5) ln e.  Note that ln e = 1 (these two functions are inverses of one another).

Then we are left with ln y = ln 5.  Dropping the "ln" operator from both sides,

y=5 (same as before).
8 0
3 years ago
Helppp What’s 35 X 49 ??
Ronch [10]

Answer:

Answer is 1715

Step-by-step explanation:

<em>DON'T</em><em> </em><em>make</em><em> </em><em>fun</em><em> </em><em>in</em><em> </em><em>brainly</em><em>. </em>

<em>this</em><em> </em><em>app</em><em> </em><em>is</em><em> </em><em>made</em><em> </em><em>to</em><em> </em><em>help</em><em> </em><em>more students in </em><em>all</em><em> </em><em>subjects</em><em>. </em><em>whatever</em><em> </em><em>don't</em><em> </em><em>do</em><em> </em><em>the</em><em> </em><em>mistakes</em><em> </em><em>again</em><em>. </em>

<em>HAVE A NICE DAY</em><em>!</em>

<em>THANKS FOR GIVING ME THE OPPORTUNITY</em><em> </em><em>TO ANSWER YOUR QUESTION</em><em>. </em>

7 0
3 years ago
Read 2 more answers
Shark Inc. has determined that demand for its newest netbook model is given by lnq−3lnp+0.004p=7ln⁡q−3ln⁡p+0.004p=7, where q is
olga2289 [7]
  <span>a) Differentiate both sides of lnq − 3lnp + 0.003p=7 with respect to p, keeping in mind that q is a function of p and so using the Chain Rule to differentiate any functions of q: 

(1/q)(dq/dp) − 3/p + 0.003 = 0 
dq/dp = (3/p − 0.003)q. 

So E(p) = dq/dp (p/q) = (3/p − 0.003)(q)(p/q) = (3/p − 0.003)p = 3 − 0.003p. 

b) The revenue is pq. 
Note that (d/dp) of pq = q + p dq/dp = q[1 + dq/dp (p/q)] = q(1 + E(p)), which is zero when E(p) = −1. Therefore, to maximize revenue, set E(p) = −1: 

3 − 0.003p = −1 
0.003p = 4 
p = 4/0.003 = 4000/3 = 1333.33</span>
8 0
3 years ago
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