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miskamm [114]
3 years ago
13

During the production of gametes, the chromosomes of a cell have condensed, and the chromatids of homologous chromosomes are cro

ssing over to form new allele combinations. Which of the following is the best conclusion you can make about the life cycle of this cell?
The cell will separate into two daughter cells next, and cytokinesis will occur.

The cell is in prophase I of meiosis and will enter metaphase I next.

The cell will make a copy of each chromosome in order to form diploid daughter cells.

The cell is in interphase II of meiosis and will enter prophase II next.
Biology
2 answers:
snow_tiger [21]3 years ago
7 0

Answer:

The correct answer will be the cell is in prophase I of meiosis and will enter metaphase I next.

Explanation:

Meiosis is a type of cell division which is involved in the formation of haploid gametes.

During meiosis the division of the genetic material is markedly observed and based on this meiosis is divided into 4 phases: prophase, metaphase, anaphase and telophase.

During prophase: the chromatin structure of DNA starts condensing to form chromatids which attaches to homologous chromatids and are known as sister chromatids. These sister chromatids exchange their genetic material via a process called called recombination or crossing over which takes place during pachytene stage of prophase I. After crossing over it is proceeded by the next stage that is metaphase I in which chromosomes gets aligned at the center of the cell.

Thus, the cell is in prophase I of meiosis and will enter metaphase I next is the correct answer.

castortr0y [4]3 years ago
6 0

Answer:

<em>The cell is in prophase I of meiosis and will enter metaphase I next</em>

Explanation:

The life cycle of the cell has 2 main phases;

  • <em>the interphase</em>
  • <em>the m phase</em>

Depending on the type of cell, the interphase include the quiescence, cell development/growth, DNA synthesis, and protein synthesis phase while the m phase is either meiotic (for sex cells) or mitotic (for vegetative cells). Meiotic cell division leads to the production of gametes while mitotic cell division leads to the production of replica daughter cells.

Meiotic cell division is a 2-stage cell division with each stage divided to <em>prophase, metaphase, anaphase</em> and <em>telophase</em>. The first stage is referred to as meiosis I and the second stage meiosis II. On a more simpler note, meiosis can be viewed as consisting of six main sub-stages including <em>prophase I, metaphase I, anaphase I, telophase I, prophase II, metaphase II, anaphase II, and telophase II.</em>

During prophase I, the nuclear materials in a cell condenses and becomes visible as threads. This stage is sometimes referred to as leptotene or leptonema stage.

Thereafter, homologous chromosomes start pairing up to form a bivalent/tetrad. Paired homologous chromosomes exchange chromosomal segments between non-sister chromatids in a process known as crossing over or genetic recombination at the pachynema stage.

Zygonema/zygotene and diplonema/diplotene stages quickly follow during which paired chromosomes disengage except at the point of crossing over.

Prophase I is completed with a process of diakiness before the cell exits to metaphase I.

<em>Thus, at the end of prophase I, chromosomes have condensed, crossing over has taken place and the cell moves to metaphase I</em>

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Answer:

  1. What is the highest number of risk units an individual can have with this model? 48 units of risk
  2. What is the phenotype of an individual of genotype AaBbCCDd? The individual has curly toes
  3. Is it possible for them to have a child with curly toes?

        Yes, the couple can have children with curly toes.

Explanation:

<u>Available data</u>:

  • The curly toe phenotype is controlled by 4 diallelic additive genes
  • Genes A, B, C, D  
  • A dominant allele has 6 units of risk
  • A recessive allele has 2 units of risk
  • Individuals with more than 35 units of risk have curly toes
  • Individuals with 35 or fewer risk units have straight toes

The term quantitative heritability refers to the transmission of a phenotypic trait in which expression depends on the additive effect of a series of genes.  

Polygenic heritability occurs when a trait results from the interaction of more than one gene. And these genes can also have more than two alleles. The action of many genes and alleles can cause many different combinations that are the reason for genotypic graduation.  

Quantitative traits are those that can be measure, such as longitude, weight, eggs laid per female, among others. These characters do not group individuals by any precise and clear categories. Instead, they group individuals in many different categories that depend on how the genes were intercrossed and distributed during meiosis. The result depends on the magnitude in which each allele contributes to the final phenotype and genotype. When they interact, they create a gradation in phenotypes, according to the level of contribution.

According to this information, and knowing how each allele contributes to the risk, we can say that the minimum units of risk are 16, determined by the recessive genotype aabbccdd. Each recessive allele contributes with 2 units of risk, so (aa=4units + bb=4 units + cc=4 units + dd=4 units) =  16 units.

Each time a dominant allele is present in the genotype, it adds 6 units to the total risk.    

What is the highest number of risk units an individual can have with this model?

48 units of risk, which corresponds to the genotype AABBCCDD. Each dominant allele contributes 6 units to the risk. There are 8 dominant alleles, so, 8x6=48 units.

What is the phenotype of an individual of genotype AaBbCCDd?

The individual has curly toes because it has a risk of 36 units, which is superior to the limit of 35 units. Dominant alleles A, B, C, C, D contribute with 30 units of risk (6x5), and recessive alleles a, b, d contribute 6 units of risk (3x2).

Cross:

Parentals) AAbbCcDd   x   AaBbCCDd

Gametes) AbCD, AbcD, AbCd, Abcd

               ABCD, ABCd, AbCD, AbCd, aBCD, aBCd, abCD, abCd

Punnett square)  AbCD                 AbcD               AbCd               Abcd

          ABCD    AABbCCDD     AABbCcDD     AABbCCDd     AABbCcDd

          ABCd    AABbCCDd      AABbCcDd     AABbCCdd      AABbCcdd

          AbCD    AAbbCCDD      AAbbCcDD    AAbbCCDd     AAbbCcDd

         AbCd     AAbbCCDd       AAbbCcDd     AAbbCCdd     AAbbCcdd

         aBCD     AaBbCCDD      AaBbCcDD      AaBbCCDd     AaBbCcDd

         aBCd     AaBbCCDd      AaBbCcDd      AaBbCCdd     AaBbCcdd

         abCD     AabbCCDD      AabbCcDD      AabbCCDd    AabbCcDd

         abCd      AabbCCDd      AabbCcDd      AabbCCdd        AabbCcdd

F1) 16 /32 = 1/2 individuals in the progeny are expected to have curly toes

     16 /32 = 1/2 individuals are expected to have straight toes

Is it possible for them to have a child with curly toes?

Yes, the couple can have children with curly toes.

To have curly toes, individuals must have more than 35 units of risk.

To have more than 35 units, individuals´ genotypes must carry at least 5 dominant alleles (which equal 30 units).

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