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babymother [125]
3 years ago
13

A rectangle is bounded by the x-axis and the semicircle y = √(36 – x^2). Write the area A of the rectangle as a function of x, a

nd determine the domain of the area function.

Mathematics
1 answer:
Dafna11 [192]3 years ago
8 0
A(x)=2x·√36-x²
this is the answer.

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Write the equation of the line perpendicular to the line x - 3y = 9 and passing through the point (3,5).
PilotLPTM [1.2K]
Here is a sample problem
has to be perpendicular to y=(4/9)*x-2 and pass through 4,3,


y-b=m(x-a)
slope of -9/4 is perpendicular to slope of 4/9, as y=4/9x-2 has slope 4/9. Our point is (4,3) therefore.
y-3=-9/4*(x-4)
y-3=-9/4x+9
y=-9/4x+9+3
y=-9/4x+12
5 0
3 years ago
A set of data has 12 pieces of data. Which of the following statements is NOT TRUE?
BARSIC [14]
To help you understand this, it is helpful to create a sample set of data:

__,__,__,(Q1 is here)__,__,__,(median is here)__, __,__,(Q3is here)__,__,__

A. The first 3 lines are 3 pieces of data in the first quartile.

B. here are 6 pieces of data between the 1st and 3rd quartiles.

D. There are 3 pieces of data in the upper quartile.
                                 

5 0
3 years ago
Find the percentage of vacationers from<br> question 10 who spent between $1500<br> and $2000.
mars1129 [50]

Answer:

The percentage change of vacationers is 33.3 %

Step-by-step explanation:

Given as :

The old value of the vacationers = $ 1500

The new value of the vacationers = $ 2000

Let the percentage variation = x %

Or, x % increase = \dfrac{\tyextrm new value - \textrm old value}{\textrm old value} × 100

Or,  x % increase = \dfrac{\tyextrm $ 2000 - \textrm $ 1500}{\textrm $ 1500} × 100

Or, x % increase = \frac{500}{1500} × 100

Or, x % increase = \frac{1}{3} × 100

Or, x % increase = \frac{100}{3}

∴  x  = 33.3 %

So, The percentage increase change is 33.3 %

Hence The percentage change of vacationers is 33.3 %   Answer

3 0
3 years ago
Write the equation for the quadratic function in standard form
Ede4ka [16]

Answer:

y=x^2+6x+7

Step-by-step explanation:

To write the quadratic in standard form, begin by writing it in vertex form

y = a(x-h)^2+k

Where (h,k) is the vertex of the parabola.

Here the vertex is (-3,-2). Substitute and write:

y=a(x--3)^2+-2\\y=a(x+3)^2-2

To find a, substitute one point (x,y) from the parabola into the equation and solve for a. Plug in (0,7) a y-intercept of the parabola.

7=a((0)+3)^2-2\\7=a(3)^2-2\\7=9a-2\\9=9a\\1=a

The vertex form of the equation is y=(x+3)^2-2.

To write in standard form, convert vertex form through the distributive property.

y=(x+3)^2-2\\y=(x^2+6x+9)-2\\y=x^2+6x+7

8 0
4 years ago
What do the meter, liter, and gram all have in common?
Margaret [11]

Answer:

They are all the basic units of measure in the metric system

Step-by-step explanation:


8 0
3 years ago
Read 2 more answers
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