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babymother [125]
3 years ago
13

A rectangle is bounded by the x-axis and the semicircle y = √(36 – x^2). Write the area A of the rectangle as a function of x, a

nd determine the domain of the area function.

Mathematics
1 answer:
Dafna11 [192]3 years ago
8 0
A(x)=2x·√36-x²
this is the answer.

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The function​ s(t) represents the position of an object at time t moving along a line. Suppose s (3 )equals 156 and s (6 )equa
bixtya [17]

Answer: The average velocity of the object over the time interval [3,6] is 20.

Step-by-step explanation:

Since we have given that

s(3) = 156

s(6) = 216

We need to find the average velocity over the time interval [3,6].

So, average velocity becomes

\dfrac{s(t_1)-s(t_0)}{t_1-t_0}\\\\=\dfrac{s(6)-s(3)}{6-3}\\\\=\dfrac{216-156}{3}\\\\=\dfrac{60}{3}\\\\=20

Hence, the average velocity of the object over the time interval [3,6] is 20.

5 0
3 years ago
How do you work out the 10th term?
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Answer:

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Step-by-step explanation:

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3 0
3 years ago
Read 2 more answers
A rectangle has an area of 0.24 of a square. What are some possibility for the length and width of the rectangle? Tell why
VLD [36.1K]

Answer:

<h3>The possibilities of length and width of the rectangle are </h3><h3>x=1, y=0.24;</h3><h3>x=0.5, y=0.48;</h3><h3>x=0.25, y=0.96;</h3><h3>x=2, y=0.12</h3>

Step-by-step explanation:

Given that the area is 0.24 square meter

The area of a rectangle is given by

Area=length\times width square units

Let x be the length and y be the width.

Since the area is 0.24 square meter, we have the equation:

Area=x\times y = 0.24, with x and y measures in meters

If we want to know some possibilities of x and y, we can assume a value for one of them, and then calculate the other one using the equation.

Now choosing some values for "x", we have:

Put x = 1

1\times y = 0.24

∴ y = 0.24

Now put x = 0.5 we get

0.5\times y = 0.24

∴ y = 0.48

Put  x = 0.25

0.25\times y = 0.24

∴ y = 0.96

Put x = 2

2\times y = 0.24

∴ y = 0.12

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3 years ago
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