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babymother [125]
3 years ago
13

A rectangle is bounded by the x-axis and the semicircle y = √(36 – x^2). Write the area A of the rectangle as a function of x, a

nd determine the domain of the area function.

Mathematics
1 answer:
Dafna11 [192]3 years ago
8 0
A(x)=2x·√36-x²
this is the answer.

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The area of a rectangle is 33 m2 ,
Vika [28.1K]

For this case we have that by definition, the area of ​​a rectangle is given by:

A = w * l

Where:

w: Is the width of the rectangle

l: is the length of the rectangle

According to the data of the statement we have:

A = 33 \ m ^ 2\\l = w-5

Substituting:

w (w-5) = 33\\w ^ 2-5w-33 = 0\\\\So:\\w = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2a}\\a = 1\\b = -5\\c = -33

Substituting the values:

w = \frac {- (- 5) \pm \sqrt {(- 5) ^ 2-4 (1) (- 33)}} {2 (1)}\\\\w = \frac {5 \pm \sqrt {25 + 132}} {2}}\\\\w = \frac {5 \pm \sqrt {157}} {2}}

Thus, we have two roots:

w_ {1} = \ frac {5+ \ sqrt {157} {2}} = 8.77

w_ {2} = \ frac {5+ \ sqrt {157} {2}} = - 3.77

We choose the positive value. So the width of the rectangle is approximately 8.77 meters and the length is 3.77 meters

Answer:

l = 3.77 \ m\\w = 8.77 \ m

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4 years ago
What is the value of the eights in 6,588
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Given 3 and 1 over 10 times negative six times 5 over 12, determine the product.
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3\frac{1}{10} \times -6\cdot \cfrac{5}{12}\implies \cfrac{3\cdot 10+1}{10} \times \cfrac{-6\cdot 5}{12}\implies \cfrac{31}{10}\times \cfrac{-6}{12}\cdot 5\implies \cfrac{31}{10}\times \cfrac{-1}{2}\cdot 5 \\\\\\ \cfrac{31}{10}\times \cfrac{-5}{2}\implies \cfrac{31\cdot -5}{10\cdot 2}\implies \cfrac{-155}{20}\implies -7\frac{3}{4}

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Please answer the questions below.
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Answer:

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Step-by-step explanation:

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Question is wrong.
it should be
cot( \frac{ \pi }{2} -x)=tanx
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3 years ago
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