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QveST [7]
3 years ago
10

Write the equation of the line perpendicular to the line x - 3y = 9 and passing through the point (3,5).

Mathematics
1 answer:
PilotLPTM [1.2K]3 years ago
5 0
Here is a sample problem
has to be perpendicular to y=(4/9)*x-2 and pass through 4,3,


y-b=m(x-a)
slope of -9/4 is perpendicular to slope of 4/9, as y=4/9x-2 has slope 4/9. Our point is (4,3) therefore.
y-3=-9/4*(x-4)
y-3=-9/4x+9
y=-9/4x+9+3
y=-9/4x+12
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Find the volume of a rectanglular prism if the length is x and the width is x^2 and the height is 5x^2 +4x+1. Use the formula v=
My name is Ann [436]

Answer:

The volume = 5x^{5}+4x^{4}+x^{3}

Step-by-step explanation:

* The rule of the volume of the rectangular prism:

- the volume of any prism = base area × height

∵ The base of the rectangular prism is rectangle

∵ Area any rectangle = Length × Width = l × w

∴ The volume of the rectangular prism = l × w × h

* In the problem:

∵ l = x , w = x² , h = 5x² + 4x + 1

∴ The volume = (x)(x²)(5x² + 4x + 1)

* We will simplify it

- Multiply x by x² and then multiply the answer by the bracket

∵ x × x² = x³

∴ x³(5x² + 4x + 1)

∵ x³ × 5x² = 5x^5

∵ x³ × 4x = 4x^4

∵ x³ × 1 = x³

∴ The volume = 5x^{5}+4x^{4}+x^{3}

5 0
3 years ago
Please help me!! Solve for 'a'. <br> b=(4*a)-3<br> ----------<br> 4
lilavasa [31]

here u go! i hope this is correct :)

8 0
2 years ago
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The area of a rectangle is (4x2 − 49y2) square units. Determine the dimensions of the rectangle by factoring the area expression
Pani-rosa [81]

Answer:

8x

Step-by-step explanation:

(4x^{2} - 49y^{2} ) = (2x+7y)(2x-7y)

4 0
3 years ago
What is the line that goes through (-5,1) and perpendicular to y= 5/4x + 3
lesya [120]
Sorry just commenting for something
5 0
3 years ago
Directions: for questions 1 through 4, find the diagonal length of each solid figure.
Alex787 [66]
\text{The length of the diagonal is }11.2\text{ mm}

Here, we want to find the diagonal of the given solid

To do this, we need the appropriate triangle

Firstly, we need the diagonal of the base

To get this, we use Pythagoras' theorem for the base

The other measures are 6 mm and 8 mm

According ro Pythagoras' ; the square of the hypotenuse equals the sum of the squares of the two other sides

Let us have the diagonal as l

Mathematically;

\begin{gathered} l^2=6^2+8^2 \\ l^2\text{ = 36 + 64} \\ l^2\text{ =100} \\ l\text{ = }\sqrt[]{100} \\ l\text{ = 10 mm} \end{gathered}

Now, to get the diagonal, we use the triangle with height 5 mm and the base being the hypotenuse we calculated above

Thus, we calculate this using the Pytthagoras' theorem as follows;

\begin{gathered} d^2=5^2+10^2 \\ d^2\text{ = 25 + 100} \\ d^2\text{ = 125} \\ d\text{ = }\sqrt[]{125} \\ d\text{ = }11.2\text{ mm} \end{gathered}

7 0
1 year ago
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