How many 2-digit numbers are multiples of 2 but not 4?

Mathematics

1 answer:

lana [24]3 years ago

6 0

There are 23 such numbers. Here they are:

10
14
18
22
26
30
34
38
42
46
50
54
58
62
66
70
74
78
82
86
90
94
98

You might be interested in

Can somebody help mee plzzzzzzzz

hammer [34]

Answer:

lines a and b are parallel. The slopes are -1/3

None of the lines are perpendicular to each other.

Step-by-step explanation:

To figure out if any of the lines are parallel or perpendicular to each other, you have to find the slopes of each line. To find the slope look at the graph find the rise over run for all of the lines:

line a: This line goes down one every time it goes over 3, which can be represented by -1/3

line b: This lines goes down one every time it goes over 3, which can also be written as -1/3

line c: This line goes up 5 every time it goes over 2, which makes the slope 5/2

When two lines are parallel, they have the same slope. Line a and line b have the same slope, so they are parallel.

When two lines are perpendicular, their slopes are negative reciprocals of each other. Since none of the slopes are a negative reciprocal of another slope, we have no perpendicular lines.

Hope this helps :)

7 0

3 years ago

What is an equation of the line that passes through the points (0, 3) and (5,-3)?

Arisa [49]

Answer:

The equation of the line that passes through the points (0, 3) and (5, -3) is $y = -\frac{6}{5}\cdot x +3$ .

Step-by-step explanation:

From Analytical Geometry we must remember that a line can be formed after knowing two distinct points on Cartesian plane. The equation of the line is described below:

$y = m\cdot x + b$ (Eq. 1)

Where:

$x$ - Independent variable, dimensionless.

$y$ - Dependent variable, dimensionless.

$m$ - Slope, dimensionless.

$b$ - y-Intercept, dimensionless.

If we know that $(x_{1},y_{1}) = (0,3)$ and $(x_{2},y_{2})=(5,-3)$ , the following system of linear equations is constructed:

$b = 3$ (Eq. 2)

$5\cdot m + b = -3$ (Eq. 3)

The solution of the system is: $b = 3$ , $m = -\frac{6}{5}$ . Hence, we get that equation of the line that passes through the points (0, 3) and (5, -3) is $y = -\frac{6}{5}\cdot x +3$ .