Problem 13
10p+10q factors to 10(p+q). If we apply the distributive property, we can distribute the 10 to each term inside (p and q) to get
10(p+q) = (10 times p)+(10 times q) = 10*p + 10*q = 10p+10q
so we get the original expression again. Here 10 is the GCF of the two terms.
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Plug p = 1 and q = 2 into the factored form
10*(p+q) = 10*(1+2) = 10*(3) = 30
As a check, let's plug those p,q values into the original expression
10*p+10*q = 10*1+10*2 = 10+20 = 30
We get the same output of 30
787-10=777
777/3=259
259 multiples of 3
Answer:
y=21.14
Step-by-step explanation:
x=6 because after 6 weeks
y= 3.27(6)+ 1.52
y=19.62 + 1.52
y=21.14
2000+1200=3200=thirty two hundreds
Answer:
it would be b for 1 since 7 would be negative and the 3 would be positive
