We can use the compound interest formula
F=P(1+i)^n
where
F=Future value of investment to be found
P=present value of investment ($1000)
i=interest per period (1/4 year)=0.04/4=0.01
n=number of periods (3 years * 4 quarters = 12)
Substitute or "Plug in" values, so to speak,
F=1000*(1+0.01)^12
use a calculator to do the sum
=1126.83 (to the nearest cent, and use the proper rounding rules)
Answer:
x=−2,−8
Step-by-step explanation:
Move terms to the left side. Then set each factor equal to zero.
x=−2,−8
Division phrases:
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Answer: f(2) = 4
Step-by-step explanation:
F(x) and g(x) are said to be continuous functions
Lim x=2 [3f(x) + f(x)g(x)] = 36
g(x) = 2
Limit x=2
[3f(2) + f(2)g(2)] = 36
[3f(2) + f(2) . 6] = 36
[3f(2) + 6f(2)] = 36
9f(2) = 36
Divide both sides by 9
f(2) = 36/9
f(2) = 4
Answer:
0.2364
Step-by-step explanation:
We will take
Lyme = L
HGE = H
P(L) = 16% = 0.16
P(H) = 10% = 0.10
P(L ∩ H) = 0.10 x p(L U H)
Using the addition theorem
P(L U H) = p(L) + P(H) - P(L ∩ H)
P(L U H) = 0.16 + 0.10 - 0.10 * p(L u H)
P(L U H) = 0.26 - 0.10p(L u H)
We collect like terms
P(L U H) + 0.10P(L U H) = 0.26
This can be rewritten as:
P(L U H)[1 +0.1] = 0.26
Then we have,
1.1p(L U H) = 0.26
We divide through by 1.1
P(L U H) = 0.26/1.1
= 0.2364
Therefore
P(L ∩ H) = 0.10 x 0.2364
The probability of tick also carrying lyme disease
P(L|H) = p(L ∩ H)/P(H)
= 0.1x0.2364/0.1
= 0.2364
