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3 years ago

Order these weights from lightest to heaviest 10 ounces 1 pond and 1 ounce

Mathematics

1 answer:

Alchen [17]3 years ago

6 0

1 ounce, 10 ounces, 1 pound.

1 pound = 16 ounces

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What is F(3) if F(x) = x3– 2x2 + 3x –12?

wariber [46]

Step-by-step explanation:

Simply input 3 for x in the equation.

$x^{3} -2x^2+3x-12\\(3)^{3} -2(3)^2+3(3)-12\\27-18+9-12\\Final answer = 6$

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2 years ago

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Write two solutions for each variable in the equations below<br><br> |a|=7

AnnyKZ [126]

Answer:

the absolute value of 7 and -7 equals 7

a=7

a=-7

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2 years ago

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Find the value of x.

Alenkinab [10]

Answer:

its 10

Step-by-step explanation:

BECAUSE OF THE FACT THAT IT CHANGED THE WAY THE DIAMETER OF HOW IT FOLDED

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2 years ago

Help please! Will give brainly! Explain how the equation y=x^2 differs from the equation y=x

ira [324]

Answer:

Below.

Step-by-step explanation:

$y=x^2$ is also $y = x*x$

It will differ for any x besides 1 and 0 because you're multiplying x by itself, which makes the answer greater.

But, it's the same for 1 and 0 because they equal each other when you square them.

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2 years ago

Sample annual salaries (in thousands of dollars) for employees at a company are listed. (a) Find the sample mean and sample s

Helen [10]

Answer:

Follows are the solution to the given points:

Step-by-step explanation:

The value is attached in the image file please find it.

In point a:

First, we calculate the find the mean,

Formula:

$\to Mean (\bar{x}) = \frac{( \sum x)}{n}$

$=\frac{540}{13}\\\\ = 41.54$

To calculate the standard deviation, subtract the mean value from all observations then square its value:

$SD = \sqrt{\frac{\sum(x-\bar{x})^2}{n-1}} \\$ $= \sqrt{ \frac{339.2308}{13-1}}$

$= \sqrt{ \frac{339.2308}{12}}\\\\= \sqrt{28.269}\\\\=5.31$

please find attached file

In point b:

New $x_i = 1 x_i + 0.05 x_i = 1.05 x_i$

Calculate new mean:

$\to \bar{x} = \frac{\sum x}{n} \\$

$=\frac{567}{13} \\\\= 43.62$

calculating the standard deviation:

$SD = \sqrt{\frac{\sum(x-\bar{x})^2}{n-1}} \\$ $= \sqrt{ \frac{374.0022}{13-1}}$

$= \sqrt{ \frac{374.0022}{12}}\\\\= \sqrt{31.16}\\\\=5.58$

please find attached file

In point C:

Calculate new mean:

$\to \bar{x} = \frac{\sum x}{n} \\$

$=\frac{47.25}{13} \\\\= 3.46$

calculating the standard deviation:

$SD = \sqrt{\frac{\sum(x-\bar{x})^2}{n-1}} \\$ $= \sqrt{ \frac{2.5975}{13-1}}$

$= \sqrt{ \frac{2.5975}{12}}\\\\= \sqrt{0.216}\\\\=0.46$

please find attached file

In point d:

for b,

New $\bar{x}= 1.05 \bar{x}= 1.05(41.54) =43.62$

New $s= 1.05s= 1.05(5.31)=5.57$

for c,

New $\bar{x}= \frac{ \bar{x}}{12}= \frac{41.54}{12} = 3.46$

New $s = \frac{s}{ 12} = \frac{5.31}{12}= 0.44$

4 0

3 years ago