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creativ13 [48]
3 years ago
15

What is the solution to the system x+y=10 3y=-3x+30 PLEASE helpppp

Mathematics
1 answer:
choli [55]3 years ago
6 0

Answer:

Step-by-step explanation:

x+y=10

x=10-y

x=10-5

x=5

3y= -3x+30

3(10-y)= -3(10-y)+30

30-3y= -30+3y+30

30+30-30=6y

30=6y

y=5

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Find the value of x in the triangle shown below
wolverine [178]

Answer:

Step-by-step explanation:

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3 years ago
A corporation has 11 manufacturing plants. Of these, seven are domestic and four are outside the United States. Each year a perf
nikdorinn [45]

Answer:

The probability that a performance evaluation will include at least one plant outside the United States is 0.836.

Step-by-step explanation:

Total plants = 11

Domestic plants = 7

Outside the US plants = 4

Suppose X is the number of plants outside the US which are selected for the performance evaluation. We need to compute the probability that at least 1 out of the 4 plants selected are outside the United States i.e. P(X≥1). To compute this, we will use the binomial distribution formula:

P(X=x) = ⁿCₓ pˣ qⁿ⁻ˣ

where n = total no. of trials

           x = no. of successful trials

           p = probability of success

           q = probability of failure

Here we have n=4, p=4/11 and q=7/11

P(X≥1) = 1 - P(X<1)

          = 1 - P(X=0)

          = 1 - ⁴C₀ * (4/11)⁰ * (7/11)⁴⁻⁰

          = 1 - 0.16399

P(X≥1) = 0.836

The probability that a performance evaluation will include at least one plant outside the United States is 0.836.

7 0
3 years ago
The equation x= -7y^2 describes a parabola. Which way does the parabola open?
Nutka1998 [239]

Answer:

Downwards

Step-by-step explanation:

8 0
2 years ago
a bag holds 1200 marbles colored either blue, red, green, or pink. there are 2 more blue than green, 6 more green than red and 6
krek1111 [17]
B = 2 + g . . . (1)
g = 6 + r . . . (2)
r = 6 + p . . . (3)

Putting (3) into (2) gives:
g = 6 + 6 + p = 12 + p . . . (4)
Putting (4) into (1) gives:
b = 2 + 12 + p = 14 + p . . . (5)

b + g + r + p = 1200
2 + g + 6 + r + 6 + p + p = 1200
2 + 12 + p + 6 + 6 + p + 6 + p + p = 1200
32 + 4p = 1200
4p = 1200 - 32 = 1168
p = 292

From (5), b = 14 + p = 14 + 292 = 306

Therefore, there are 306 blue mables.
8 0
3 years ago
(x +y)^5<br> Complete the polynomial operation
Vesna [10]

Answer:

Please check the explanation!

Step-by-step explanation:

Given the polynomial

\left(x+y\right)^5

\mathrm{Apply\:binomial\:theorem}:\quad \left(a+b\right)^n=\sum _{i=0}^n\binom{n}{i}a^{\left(n-i\right)}b^i

a=x,\:\:b=y

=\sum _{i=0}^5\binom{5}{i}x^{\left(5-i\right)}y^i

so expanding summation

=\frac{5!}{0!\left(5-0\right)!}x^5y^0+\frac{5!}{1!\left(5-1\right)!}x^4y^1+\frac{5!}{2!\left(5-2\right)!}x^3y^2+\frac{5!}{3!\left(5-3\right)!}x^2y^3+\frac{5!}{4!\left(5-4\right)!}x^1y^4+\frac{5!}{5!\left(5-5\right)!}x^0y^5

solving

\frac{5!}{0!\left(5-0\right)!}x^5y^0

=1\cdot \frac{5!}{0!\left(5-0\right)!}x^5

=1\cdot \:1\cdot \:x^5

=x^5

also solving

=\frac{5!}{1!\left(5-1\right)!}x^4y

=\frac{5}{1!}x^4y

=\frac{5}{1!}x^4y

=\frac{5x^4y}{1}

=\frac{5x^4y}{1}

=5x^4y

similarly, the result of the remaining terms can be solved such as

\frac{5!}{2!\left(5-2\right)!}x^3y^2=10x^3y^2

\frac{5!}{3!\left(5-3\right)!}x^2y^3=10x^2y^3

\frac{5!}{4!\left(5-4\right)!}x^1y^4=5xy^4

\frac{5!}{5!\left(5-5\right)!}x^0y^5=y^5

so substituting all the solved results in the expression

=\frac{5!}{0!\left(5-0\right)!}x^5y^0+\frac{5!}{1!\left(5-1\right)!}x^4y^1+\frac{5!}{2!\left(5-2\right)!}x^3y^2+\frac{5!}{3!\left(5-3\right)!}x^2y^3+\frac{5!}{4!\left(5-4\right)!}x^1y^4+\frac{5!}{5!\left(5-5\right)!}x^0y^5

=x^5+5x^4y+10x^3y^2+10x^2y^3+5xy^4+y^5

Therefore,

\left(x\:+y\right)^5=x^5+5x^4y+10x^3y^2+10x^2y^3+5xy^4+y^5

6 0
3 years ago
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