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3 years ago

Are they simular and why

Mathematics

1 answer:

S_A_V [24]3 years ago

4 0

Answer:

YES

Step-by-step explanation:

because there the same shape but the right one is moved to the side a little bit

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1. (1 pt) Which is a solution to the equation y=3x+1 ?A. (3, 10) B. (2, 6) C. (1, 5) D. (0, 3)

frozen [14]

Answer:

the easy way to figure this out is to just plug in answers.

start with a, (10)=3(3)+1

10=9+1

10=10

this makes this a true statement

feel free to try the other options but this is your answer

A. (3,10)

7 0

2 years ago

Choices:<br> A. 3/16<br> B.3/11<br> C. 5/11<br> D. 5/16

Natali [406]

Answer:

Step-by-step explanation:

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2 years ago

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A composition that involves a translation and a reflection is called a ____________.

Olegator [25]

I think it is a glide reflection.

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3 years ago

Help please!!! You are Miguel Cervantes de Navas y Colon, captain in the Royal Spanish Army in Sevilla in the year 1842

tiny-mole [99]

Answer:

There are 650 cannonballs

Step-by-step explanation:

If you look closely in the picture, you can see that:

1st row has 1 ball
2nd row has 4 balls
3rd row has 9 balls
4th row has 16 balls

etc. etc.

We can see that the number of balls is the square of the row number. There are a total of 12 rows. So, rest of the rows has:

5th row has 25 balls
6th row has 36 balls
7th row has 49 balls
8th row has 64 balls
9th row has 81 balls
10th row has 100 balls
11th row has 121 balls
12th row has 144 balls

If we add up all those, we get total number of balls:

$1+4+9+16+25=36+49+64+81+100+121+144=650$

There are 650 cannonballs

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3 years ago

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Solve the system using substitution x+5y=0 3y+2x=-21

Crazy boy [7]

Answer:

$\left \{ {{x = -15} \atop {y=3}} \right.$

Step-by-step explanation:

$\left \{ {{x + 5y = 0} (1) \atop {3y + 2x = -21}(2)} \right. \left \{ {{x = -5y} \atop {3y + 2x = -21}} \right. \left \{ {{x = -5y} \atop {3y + 2*(-5y) = -21}} \right. \left \{ {{x = -5y} \atop {3y - 10y = -21}} \right. \\ \left \{ {{x = -5y } \atop {-7y = -21}} \right. \left \{ {{x = -5y} \atop {y= 3 }} \right. \left \{ {{x = -5 * 3} \atop {y=3}} \right.=> \left \{ {{x=-15} \atop {y=3}} \right.$

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2 years ago

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Are they simular and why​

Are they simular and why